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WARRIOR [948]
3 years ago
12

When 50.0 mL of 1.000 M HCl is reacted with 50.0 mL of 1.000 M NH4OH, the solution's temperature increases 8.65 °C. Calculate qs

olution in units of kJ. The specific heat of the salt solution is 4.184 J/g-°C and the density is 1.010 g/mL.
Chemistry
1 answer:
velikii [3]3 years ago
8 0

Answer:

Explanation:

Total volume of solution = 100 mL .

Total mass of the solution = 100 x 1.01 g

= 101 g

specific heat of solution = 4.184 J/g-°C

rise in temperature = 8.65  °C

heat released = mass x specific heat x rise in temperature

= 101 x 4.184 x 8.65

= 3655.35 J

= 3.655 kJ .

qsolution = 3.655 kJ .

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Answer:

(a) adding 0.050 mol of HCl

Explanation:

A buffer is defined as the mixture of a weak acid and its conjugate base -or vice versa-.

In the buffer:

1.0L × (0.10 mol / L) = 0.10 moles of HF -<em>Weak acid-</em>

1.0L × (0.050 mol / L) = 0.050 moles of NaF -<em>Conjugate base-</em>

-The weak acid reacts with bases as NaOH and the conjugate base reacts with acids as HCl-

Thus:

<em>(a) adding 0.050 mol of HCl:</em> The addition of 0.050moles of HCl produce the reaction of 0.050 moles of NaF producing HF. That means after the reaction, all NaF is consumed and you will have in solution just the weak acid <em>destroying the buffer</em>.

(b) adding 0.050 mol of NaOH: The NaOH reacts with HF producing more NaF. Would be consumed just 0.050 moles of HF -remaining 0.050 moles of HF-. Thus, the buffer <em>wouldn't be destroyed</em>.

(c) adding 0.050 mol of NaF: The addition of conjugate base <em>doesn't destroy the buffer</em>

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3 years ago
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Answer:

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We have the final answer as

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