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WARRIOR [948]
3 years ago
12

When 50.0 mL of 1.000 M HCl is reacted with 50.0 mL of 1.000 M NH4OH, the solution's temperature increases 8.65 °C. Calculate qs

olution in units of kJ. The specific heat of the salt solution is 4.184 J/g-°C and the density is 1.010 g/mL.
Chemistry
1 answer:
velikii [3]3 years ago
8 0

Answer:

Explanation:

Total volume of solution = 100 mL .

Total mass of the solution = 100 x 1.01 g

= 101 g

specific heat of solution = 4.184 J/g-°C

rise in temperature = 8.65  °C

heat released = mass x specific heat x rise in temperature

= 101 x 4.184 x 8.65

= 3655.35 J

= 3.655 kJ .

qsolution = 3.655 kJ .

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Which of the following is not true? a. The freezing point of sea water is lower than the freezing point of pure water. b. The bo
Anna007 [38]

Answer:

The false statement is b.

The boiling point of a water sample from the Salt Lake is lower than the boiling point of pure water

Explanation:

This excersise refers to colligative properties.

Boiling point refers to the property of boiling point elevation. In a solution of ions, as water sea or water from lakes, the boiling point will be higher than water pure.

It is logical to say that, because these sort of water have ions. Remember that colligative properties depends on the solute particles.

T° boiling solution - T° pure solvent = Kb . m . i

In the freezing point depression, we have the oppossite of boiling point elevation. Freezing point of solution is lower than pure solvent, according to this:

T° freezing pure solvent - T° freezing solution = Kc . m . i

We have to always consider the i, which means Van't Hoff factor, number of ions dissolved in solution. As the i is higher, the freezing point of solution will be lower, and the boiling point of solution will be higher.

They are true statement a and c.

In solution of., [NaCl] = 0.1M, as it is a higher concentration, the molality is also higher than a solution of [NaCl] = 0.05.

As water sample form Salt Lake has certain ions, it is logical to say that the boiling point of this water is higher than boiling point of pure water.

5 0
3 years ago
HELPPP!!
lord [1]

Answer:

The anion at the end on the compound

Explanation:

to check whether a substance is soluble or not, you would find the anion at the end of the compound on a solubility chart and then see from there whether it is soluble or not

5 0
3 years ago
This one two!!!!!!!lol
Rasek [7]

Answer:

Infrared thermography

Explanation:

Infrared thermography is equipment or method, which detects infrared energy emitted from object, converts it to temperature, and displays image of temperature distribution. ... We call our equipment as infrared thermography considering such generalization of the terminology.

6 0
3 years ago
Need Some Quick Help, Please :)
Ray Of Light [21]
I think that it is D because the higher the molecular mass, the higher it's boiling point. I hope that helped:) Bye!
6 0
3 years ago
Molybdenum has a molar mass of 95.94g/mol. How many molecules of molybdenum are in 150.0 g of molybdenum
Kitty [74]
We are given the molar mass of Molybdenum as 95.94 g/mol. Also, the chemical symbol for Molybdenum is Mo. This question is asking for the amount of molecules of molybdenum in a 150.0 g sample. However, since molybdenum is a metal and it is in the form of solid molybdenum, Mo (s), it is not actual a molecule. A molecule has one or more atom bonded together. We will instead be finding the amount of atoms of Molybdenum present in the sample. To do this we use Avogadro's number, which is the amount of atoms/molecules of a substance in 1 mole of that substance.

150.0 g Mo/ 95.94 g/mol = 1.563 moles of Mo

1.563 moles Mo x 6.022 x 10²³ atoms/mole = 9.415 x 10²³ atoms Mo

Therefore, there are 9.415 x 10²³ atoms of Molybdenum in 150.0 g.
5 0
3 years ago
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