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Debora [2.8K]
2 years ago
12

A mini game cube is covered in different colors and has a side length of 1.8 inches. Which of the following would represent the

amount of space covered in various colors? *

Mathematics
1 answer:
svet-max [94.6K]2 years ago
7 0

complete question:

A mini game cube is covered in different  colors and has a side length of 1.8 inches.  Which of the following would represent the  amount of space covered in various colors?

A. 116.64 in2

B. 3.24 in2

C. 19.44 in2

D. 10.8 in2

Answer:

C. 19.44 in2

Step-by-step explanation:

A cube is a 3 dimensional figure bounded by 6 square faces. All the sides of a cube are equal in length. The picture below is a cube. The amount of space covered in different colors will be the surface area of the cube.

surface area = 6L²

where

L = length

L = 1.8 inches

surface area =  6 × 1.8²

surface area  = 6 × 3.24

surface area = 19.44 inches²

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The points (–5, 6) and (5, 6) are vertices of a hexagon. The line segment joining the two points forms one of the sides of the h
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What are the solutions of the inequality? -2(3x + 2) ≥ -6x - 4 Question 2 options: all real numbers x ≤ 6 no solution x ≥ 0
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Solution, -2\left(3x+2\right)\ge \:-6x-4\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:True\quad \forall \:x\in \mathbb{R}\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}

Steps:

-2\left(3x+2\right)\ge \:-6x-4

\mathrm{Expand\:}-2\left(3x+2\right),\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac,\\a=-2,\:b=3x,\:c=2,\\-2\cdot \:3x+\left(-2\right)\cdot \:2,\\\mathrm{Apply\:minus-plus\:rules},\\+\left(-a\right)=-a,\\-2\cdot \:3x-2\cdot \:2,\\\mathrm{Simplify}\:-2\cdot \:3x-2\cdot \:2,\\\mathrm{Multiply\:the\:numbers:}\:2\cdot \:3=6,\\-6x-2\cdot \:2,\\\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2=4,\\-6x-4,\\-6x-4\ge \:-6x-4

\mathrm{Add\:}4\mathrm{\:to\:both\:sides},\\-6x-4+4\ge \:-6x-4+4

\mathrm{Simplify},\\-6x\ge \:-6x

\mathrm{Add\:}6x\mathrm{\:to\:both\:sides},\\-6x+6x\ge \:-6x+6x

\mathrm{Simplify},\\0\ge \:0

\mathrm{Therefore,\:the\:final\:solution\:is},\\True\quad \forall \:x\in \mathbb{R}

Or\:No\:Solution\:x\geq 0


8 0
2 years ago
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