Answer:
Base Mg(OH)2 does neutralise the acid and is 12g in excess.
Explanation:
2HCL +Mg(OH)2 -> MgCl2 + 2H20
2 * 36.458 g of HCL react with 58.319 g of Mg(OH)2 to neutralise it.
72.916 HCl reacts with 58.319 g of the base.
So 20 g HCl reacts with (58.319/72.916) * 20 = 16g.
There are 28 g of Mg(OH)2 so the base does neutralise all the acid.
The Mg(OH)2 is 28 - 16 = 12 g in excess.
Three that is the answer to your question
Answer:
is there a pic or anything?
Answer:
sorry if this is wrong but B
Explanation:
Answer:
120 grams
Explanation:
Data:
Volume = V= 2 L
Molarity = 1.5 M
Molecular masses:
Na = 23, O= 16, H=1
Total molecular mass =M= 23+16+1 = 40
mass = m = ?
To find the mass we need to find moles from molarity formula:
Molarity = n/V
n= Molarity x V
= 1.5 x 2
n= 3 moles
Now we can find mass:
number of moles = given mass / molecular mass
n = m/M
m= n x M
= 3 x 40
m = 120 grams