Answer:
38.4 mol LiOH
Explanation:
Step 1: Write the balanced neutralization equation
2 LiOH + CO₂ ⇒ Li₂CO₃ + H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of LiOH to CO₂ is 2:1.
Step 3: Calculate how many moles of lithium hydroxide are required to react with 19.2 mol CO₂
19.2 mol CO₂ × 2 mol LiOH / 1 mol CO₂ = 38.4 mol LiOH
We assume that the method that made use of urea was able to recover all of the recoverable substance. The method in question is the method that makes use of water.
The total amount of substance is 43 mg/dl. The recovered amount is 25 mg/dl. The percent recovery is
(25 mg/dl / 43 mg/dl) * 100 = 58.14%
I think that's called "Trajectory"
Alkaline solutions are basic so answer is C basic