Question

Dave and Alex push on opposite ends of a car that has a mass of 875 kg. Dave pushes the car to the right with a force of 250 N, and Alex pushes to the
left with a force of 315 N. Assume there is no friction.
What is the net force on the car in the x-direction? Help meee please

Answer 1

The net force acting on the car is 65 N to the left

The net force acting on an object is simply defined as the resultant force acting on the object.

From the question given, we obtained the following data:

• Force applied to the right (Fᵣ) = 250 N
• Force applied to the left (Fₗ) = 315 N
• Net force (Fₙ) =?

The net force acting on the car can be obtained as follow:

Fₙ = Fₗ – Fᵣ

Fₙ = 315 – 250

Fₙ = 65 N to the left

Therefore, the net force acting on the car is 65 N to the left

Learn more on net force: brainly.com/question/19549734

Answer 2

Since there is no friction, the net force on the car in the x - direction will be 65 Newtons

Given that Dave and Alex push on opposite ends of a car that has a mass of 875 kg.

Dave pushes the car to the right with a force of 250 N, which is positive direction and Alex pushes to the left with a force of 315 N which is negative direction. Since there is no friction, only the horizontal forces will be considered.

To calculate the net force on the car in the x-direction, we will find the difference between the two forces because of their directions are opposite to each other.

Net force = 315 - 250

Net force = 65 Newtons

Therefore, the net force on the car in the x - direction will be 65 Newtons

Learn more about resolution of forces here: brainly.com/question/11556949