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Svetllana [295]
2 years ago
8

Dave and Alex push on opposite ends of a car that has a mass of 875 kg. Dave pushes the car to the right with a force of 250 N,

and Alex pushes to the
left with a force of 315 N. Assume there is no friction.
What is the net force on the car in the x-direction? Help meee please
Physics
2 answers:
White raven [17]2 years ago
8 0

The net force acting on the car is 65 N to the left

The net force acting on an object is simply defined as the resultant force acting on the object.

From the question given, we obtained the following data:

  • Force applied to the right (Fᵣ) = 250 N
  • Force applied to the left (Fₗ) = 315 N
  • Net force (Fₙ) =?

The net force acting on the car can be obtained as follow:

Fₙ = Fₗ – Fᵣ

Fₙ = 315 – 250

<h3>Fₙ = 65 N to the left </h3>

Therefore, the net force acting on the car is 65 N to the left

Learn more on net force: brainly.com/question/19549734

zvonat [6]2 years ago
5 0

Since there is no friction, the net force on the car in the x - direction will be 65 Newtons

Given that Dave and Alex push on opposite ends of a car that has a mass of 875 kg.

Dave pushes the car to the right with a force of 250 N, which is positive direction and Alex pushes to the left with a force of 315 N which is negative direction. Since there is no friction, only the horizontal forces will be considered.

To calculate the net force on the car in the x-direction, we will find the difference between the two forces because of their directions are opposite to each other.

Net force = 315 - 250

Net force = 65 Newtons

Therefore, the net force on the car in the x - direction will be 65 Newtons

Learn more about resolution of forces here: brainly.com/question/11556949

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a)he angle is 90 with respect to the horizontal (x axis)

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Explanation:

This is a relative problem and movement.

            .v ’= v + u

Where v ’is the speed with respect to the mobile system, v the speed with respect to the fixed system and the speed between the two reference systems

a) The child and the can is in the truck, so they go at the speed of the truck, when he throws the can he continues at this speed on the x-axis and therefore as the two advance the same distance the more hands of the child, consequently the can is thrown vertically

The angle is 90 with respect to the horizontal (x axis)

b) with respect to the truck, the can is still, so its speed is zero both vertically and horizontally

c) The child sees that the can follows a vertical path

d) A stationary observer on the ground, sees that the can has a constant speed in the same direction of the truck and when they throw it vertical goal has a vertical movement, the sum of these two movements gives a parabolic movement of the same uncle as a projectile launch

e) the initial speed has two components

X Axis         v_lata = v_camion = 9.5 m / s

Y Axis          speed given by the child

Let's look for the travel time

         x = v₀ₓ t

         t = x / v₀ₓ

         t = 16 / 9.5

         t = 1.68 s

     

         y = v_{oy} t - ½ g t²

When he returns to the child's hand and = 0

          0 = v_{oy} t - ½ g t²

          v_{oy} = ½ g t

          v_{oy} = ½  9.8  1.68

          v_{oy} = 8,232 m / s

Speed ​​is

         v₀ = (9.5i ^ + 8.232 j ^) m / s

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