Answer:
B. 0.552
Explanation:
To find the resistance in the circuit above, u simply divide the current in the circuit by the voltage to get the resistance.
Answer:
![v=2019.09\ m.s^{-1}](https://tex.z-dn.net/?f=v%3D2019.09%5C%20m.s%5E%7B-1%7D)
Explanation:
Given:
- time taken by the sun to complete one revolution,
![t=601.2\ hr](https://tex.z-dn.net/?f=t%3D601.2%5C%20hr)
- radial distance of the sunspot,
![r=6.955\times 10^8\ m.s^{-1}](https://tex.z-dn.net/?f=r%3D6.955%5Ctimes%2010%5E8%5C%20m.s%5E%7B-1%7D)
<u>Therefore, angular speed of rotation of sun:</u>
![\omega=\frac{2\pi}{601.2\times 3600} \ rad.s^{-1}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B2%5Cpi%7D%7B601.2%5Ctimes%203600%7D%20%5C%20rad.s%5E%7B-1%7D)
<u>Now the tangential velocity of the sunspot can be given by:</u>
![v=r.\omega](https://tex.z-dn.net/?f=v%3Dr.%5Comega)
![v=6.955\times 10^8\times \frac{2\pi}{601.2\times 3600}](https://tex.z-dn.net/?f=v%3D6.955%5Ctimes%2010%5E8%5Ctimes%20%5Cfrac%7B2%5Cpi%7D%7B601.2%5Ctimes%203600%7D)
![v=2019.09\ m.s^{-1}](https://tex.z-dn.net/?f=v%3D2019.09%5C%20m.s%5E%7B-1%7D)
So the question ask to formulate an expression to represent the amount of air required to inflate the balloon from a radius of R+4 and the expression would be V=16pi/3*(3r^2+12r+16). I hope you are satisfied with my answer and feel free to ask for more if you have question and further clarifications
An increase in humidity can strengthen the water cycle, because humidity is essentially boosted evaporation. When you have evaporation, that comes automatically with condensation and precipitation, so rain and cloud cover increases.
Answer:
Rp = 10 Ohms; I = 0.9 Amps
Explanation:
Since, there are two resistors each with 20Ω connected in parallel, the total resistance of the combination (Rp) of the circuit is as follows:
i.e 1/Rp = (1/R1 + 1/R2)
1/Rp = (1/20Ω + 1/20Ω)
1/Rp = (1 + 1)/20Ω
1/Rp = 2/20Ω
1/Rp = 1/10Ω
To get the value of Rp, cross multiply
Rp x 1 = 10Ω x 1
Rp = 10Ω
Apply the formula
Voltage V = Current I x Total resistance Rp
I = V/Rp
I = 9V/10Ω
I = 0.9 Amps
Thus, the total resistance is 10 Ohms, the current through the ammeter is 0.9 Amps