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3 years ago

How is the structure around a given atom related to repulsion between valence electron pairs on the atom involved

Chemistry

1 answer:

serious [3.7K]3 years ago

5 0

Answer:

Valence electron pairs are the total sum of lone pairs and bond pairs in the molecule. The electrons possess negative charge on them. They repel each other due to the presence of same charge. The lone pairs repel other electrons strongly, which are present around the central atom.

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A wafer of gold measuring 15 cm x 20 cm has a mass of 600 g. How thick is this wafer in mm ?

Gre4nikov [31]

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3 years ago

(d) carbon monoxide

Irina18 [472]

Answer:

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2 years ago

Consider the reaction below. Initially the concentration of SO2Cl2 is 0.1000 M. Solve for the equilibrium concentration of SO2Cl

tensa zangetsu [6.8K]

Answer:

$[SO_2Cl_2] = 0.09983 M$

Explanation:

Write the balance chemical equation ,

$SO_2Cl_2((g) = SO_2(g) + Cl_2(g)$

initial concenration of $SO_2Cl_2((g) =0.1M$

lets assume that degree of dissociation= $\alpha$

concenration of each component at equilibrium:

$[SO_2Cl_2] = 0.1-0.1\alpha$

$[SO_2] = 0.1\alpha$

$[Cl_2] = 0.1\alpha$

$Kc =\frac{0.1\alpha \times 0.1\alpha}{0.1-0.1\alpha}$

$Kc =\frac{0.1\alpha \times \alpha}{1-\alpha}$

as $\alpha$ is very small then we can neglect $1-\alpha$

therefore ,

$Kc ={0.1\alpha \times \alpha}$

$\alpha =\sqrt{\frac{Kc}{0.1}}$

$\alpha = 1.73 \times 10^{-3}$

Eqilibrium concenration of $[SO_2Cl_2] = 0.1-0.1\alpha = 0.1-0.1\times 0.00173$

$[SO_2Cl_2] = 0.09983 M$

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3 years ago

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Sound
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3 years ago