The layering of eroded sediments is called:

Wine goes bad soon after opening because the ethanol (CH3CH2OH) dissolved in it reacts with oxygen (O2) gas to form water and aq

andrezito [222]

The number of mole of oxygen needed is of 0.080 mole.

To solve this question, we'll begin by writing the balanced equation for the reaction. This is illustrated below:

From the balanced equation above,

2 moles of O₂ reacted to produce 2 moles of H₂O.

Finally, we shall determine the number of mole of O₂ needed to produce 0.080 mole of H₂O. This can be obtained as follow:

From the balanced equation above,

2 moles of O₂ reacted to produce 2 moles of H₂O.

Therefore,

0.080 mole of O₂ will also react to produce 0.080 mole of H₂O.

Thus, 0.080 mole of oxygen, O₂, is needed for the reaction.

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7 0

3 years ago

The person writes a coefficient of 2 in front of Fe2O3 but then writes a 4 for the number of iron (Fe) atoms. Explain this diffe

den301095 [7]

Answer:

See explanation

Explanation:

Given that the formula of the compound is Fe2O3, if a coefficient of 2 is placed in front of the formula, that is, if we write 2Fe2O3 . Then;

The number of Fe atoms becomes 2 *2 = 4

The number of oxygen atoms becomes 2*3 = 6

That is why the total number of iron atoms were written down as 4.

6 0

3 years ago

Read 2 more answers

Briefly compare and contrast the relative resistance to ph change of the seven solutions

JulsSmile [24]

PH stands for "Potential Hydrogen" and the PH scale ranges from 0-14. PH refers to the ability to attract hydrogen ions.

The PH of a solution either indicates acidity of the solution or alkalinity of the solution. A solution which has PH 7 above is a base solution where a solution with PH less than 7 is an acidic solution.

6 0

3 years ago

What is the % dissociation of a solution of acetic acid if at equilibrium the solution has a pH = 4.74 and a pKa = 4.74?

Ymorist [56]

Answer:

$\% diss = 50\%$

Explanation:

Hello there!

In this case, when considering weak acids which have an associated percent dissociation, we first need to set up the ionization reaction and the equilibrium expression:

$HA\rightleftharpoons H^++A^-\\\\Ka=\frac{[H^+][A^-]}{[HA]}$