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2 years ago

What is the acceleration of the object? 0 m/s2 0.25 m/s2 4 m/s2 8 m/s2

Physics

2 answers:

Naya [18.7K]2 years ago

6 0

The answer is 4 m/s^2.
Acceleration = Δv/Δt

aev [14]2 years ago

6 0

Acceleration = (change in speed) / (time for the change) .

That's just the slope of the graph.

It's 4 m/s² .

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What is sound wave and examples

Nezavi [6.7K]

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3 years ago

Jonas and his family are moving to another part of the city. As Jonas, his brother, and his Dad were driving one of the trucks f

vredina [299]

Answer:

i think the answer would be:Jonas’ brother gets out of the cab of the truck and sits in the back of the truck with the furniture. With less mass, they should be able to push the truck to the gas station.

Explanation:

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3 years ago

Read 2 more answers

A rock that has deformed ____ under stress keeps its new shape when the stress is released.

Anna007 [38]

Answer:

Elastically

Explanation:

A rock that has deformed Elastically under stress keeps its new shape when the stress is released.

In elastic deformation the original shape of the object is regained when the stress is removed. Whereas in plastic deformation the original shape is parmanently deformed with the application of stress.

8 0

3 years ago

Small-plane pilots regularly compete in "message drop" competitions, dropping heavy weights (for which air resistance can be ign

iren [92.7K]

plane is flying at an altitude of 70 m

now if an object is dropped from it then time taken by object to drop on ground will be given as

$y = v_i* t + \frac{1}{2}at^2$

here initial speed in vertical direction must be zero as plane is moving horizontal

given that

y = 70 m

a = 9.8 m/s^2

$70 = 0 + \frac{1}{2}*9.8*t^2$

$t = 3.77 s$

now since the plane is moving horizontally with speed v = 44 m/s

so the horizontal distance moved by the object will be

$d = v_x * t$

$d = 44 * 3.77$

$d = 166.3 m$

so the distance moved by the box is 166.3 m

3 0

2 years ago

Read 2 more answers

Assuming a vertical trajectory with no drag, derive the applicable form of the rocket equation for this application

VARVARA [1.3K]

Answer:

The vertical trajectory is governed by Ordinary Differential Equation.

Time derivatives of each state variables.

d(d)/dt = v, d(m)/dt = -d(m-fuel)/dt, d(v)/dt = F/m.

Where V is velocity positive upwards, t is time, m is mass, m-fuel is fuel mass, F is Total force, positive upwards.

Therefore,

F = -mg - D + T, If V is positive and

F = -mg + D - T, If T is negative.

D is drag and the questions gave it as zero.

Explanation:

The two sign cases in derivative equations above are required because F is defined positive up, so the drag D and thrust T can subtract or add to F depending in the sign of V . In contrast, the gravity force contribution mg is always negative. In general, F will be some function of time, and may also depend on the characteristics of the particular rocket. For example, the T component of F will become zero after all the fuel is expended, after which point the rocket will be ballistic, with only the gravity force and the aerodynamic drag force being p

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3 years ago