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brilliants [131]
3 years ago
15

What is the acceleration of the object? 0 m/s2 0.25 m/s2 4 m/s2 8 m/s2

Physics
2 answers:
Naya [18.7K]3 years ago
6 0
The answer is 4 m/s^2.
Acceleration = Δv/Δt
aev [14]3 years ago
6 0

Acceleration  =  (change in speed)  /  (time for the change) .

That's just the slope of the graph.

It's  4 m/s²  .
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Wyatt is moving a box with a mass of 37 kg a distance of 37 meters. Wyatt did 360 J of work in 2 minutes when moving the box. Wh
Elza [17]

Answer:

the answer should be 550 j because i just did it

Explanation:

all you have to do is add all of them up and get your answer

7 0
4 years ago
Why is important the electromagnetism, diff usages, and how will be our World without it
lawyer [7]

Answer:

Electromagnetism has important scientific and technological applications. It is used in many electrical appliances to generate desired magnetic fields. It is even used in a electric generator to produce magnetic fields for electromagnetic induction to occur. It has many more technological applications including MRI scanning (magnetic resonance imaging) and electric bells.

Explanation:

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7 0
3 years ago
Which statements best describe the atoms of the gas neon? Check all that apply.
Anni [7]
What are the statements?

5 0
3 years ago
Read 2 more answers
A marble accelerates from rest at a constant rate .it travels 36 m in 12.0 sec what’s is it’s final velocity and what was the ac
ddd [48]

Answer:

a = 0.50 m/s²

v = 6.0 m/s

Explanation:

Step 1: Given data

  • Initial velocity (u): 0 m/s (rest)
  • Displacement of the marble (s): 36 m
  • Time elapsed (t): 12.0 s
  • Final velocity (v): ?
  • Acceleration (a): ?

Step 2: Calculate the acceleration

We will use the following suvat equation.

s = u × t + 1/2 × a × t²

s = 0 × 12.0 s + 1/2 × a × (12.0 s)²

36 m = a × 72.0 s²

a = 0.50 m/s²

Step 3: Calculate the final velocity

We will use the following suvat equation.

v = u + a × t

v = 0 + 0.50 m/s² × 12.0 s

v = 6.0 m/s

4 0
4 years ago
A conducting sphere 45 cm in diameter carries an excess of charge, and no other charges are present. You measure the potential o
uysha [10]

Answer:

The excess charge is Q  = 3.5 *10^{-7} \ C

Explanation:

From the question we are told that

      The diameter is d = 45 \ cm  =  0.45 \ m

       The potential of the surface is V =  14 \ kV   =  14 *10^{3} \ V

     

The radius of the sphere is  

           r = \frac{d}{2}

substituting values

          r = \frac{0.45}{2}

         r = 0.225 \ m

The potential on the surface is mathematically represented as  

          V  =  \frac{k  *  Q  }{r }

Where k is coulomb's constant with value  k  =  9*10^{9}  \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.

  given from the question that there is no other charge the Q is the excess charge  

Thus  

        Q  =  \frac{V* r}{ k}

substituting values

        Q  =  \frac{14 *10^{3}  0.225}{ 9*10^9}

        Q  = 3.5 *10^{-7} \ C

         

7 0
3 years ago
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