Answer:
See explanation
Explanation:
The reaction between alcohol and acidified potassium dichromate is a redox reaction. This reaction can be used to detect a drunken driver.
Alcohols can be oxidized to aldehydes, ketones and carboxylic acids depending on the structure of the alcohol. Primary alcohols yield adehydes and carboxylic acids while secondary alcohols are oxidized to ketones.
The colour of the acidified potassium dichromate turns from orange to green when exposed to alcohols from the breath of a drunken driver.
Answer:
The density of the ideal gas is directly proportional to its molar mass.
Explanation:
Density is a scalar quantity that is denoted by the symbol ρ (rho). It is defined as the ratio of the mass (m) of the given sample and the total volume (V) of the sample.
......equation (1)
According to the ideal gas law for ideal gas:
......equation (2)
Here, V is the volume of gas, P is the pressure of gas, T is the absolute temperature, R is Gas constant and n is the number of moles of gas
As we know,
The number of moles: 
where m is the given mass of gas and M is the molar mass of the gas
So equation (2) can be written as:
⇒ 
⇒ 
......equation (3)
Now from equation (1) and (3), we get
⇒ Density of an ideal gas: 
⇒ <em>Density of an ideal gas: ρ ∝ molar mass of gas: M</em>
<u>Therefore, the density of the ideal gas is directly proportional to its molar mass. </u>
Aqueous solutions of barium nitrate and potassium phosphate are mixed.
What is the precipitate and how many molecules are formed?
Barium nitrate has a chemical symbol of Ba(NO3)2 and potassium phosphate
has a chemical symbol K2PO4. The reaction between these two is a double
replacement reaction yielding barium phosphate and potassium nitrate.
The chemical equation representing the reaction is,
Ba(NO3)2 + K2PO4 à KNO3 +
BaPO4
Answer:
I think that it might be cytoplasm
Explanation:
I got this from google
Cytoplasm is a thick solution that fills each cell and is enclosed by the cell membrane. It is mainly composed of water, salts, and proteins.
Answer:
After complete reaction, 0.280 moles of ammonia are produced
Explanation:
Step 1: Data given
Number of moles N2 = 0.140 moles
Number of moles H2 = 0.434 moles
Step 2: The balanced equation
N2(g) + 3H2 (g) ⟶ 2NH3 (g)
Step 3: Calculate the limiting reactant
For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3
N2 is the limiting reactant. It will completely be consumed (0.140 moles).
H2 is in excess. There will react 3*0.140 = 0.420 moles
There will remain 0.434 - 0.420 = 0.014 moles
Step 4: Calculate moles NH3
For 0.140 moles N2 we'll have 2*0.140 = 0.280 moles NH3
After complete reaction, 0.280 moles of ammonia are produced
