Question

How much heat is given off when 18.5g of water at 35.0 degrees Celsius freezes to ice at -5.00 degrees Celsius

Answer 1

9086.3J

Explanation:

Given parameters:

Mass of water = 18.5g

Initial temperature of water = 35°C

Finial temperature = -5°C

Unknown:

Amount of heat given off = ?

Solution:

In converting the water to ice, the water goes through these  processes:

   35°C  to freezing point at 0°C   =  mcΔT

   0°C  of water to 0°C of ice = mL

   0°C of ice to -5°C  = mcΔT

The heat given off;

 H = mc₁ΔT  +  mL  +  mc₂ΔT

m is the mass of water

c₁ is the specific heat capacity of water = 4.2J/g °C

c₂ is the specific heat capacity of ice = 2.03J/g °C

L is the latent heat of fusion = 334J/g

ΔT = T₂ - T₁ = temperature change

H = 18.5 x 4.2 + (0-(-35)) + (18.5 x 334) + (18.5 x 2.03 x (-5 - (0))

H = 2719.5J  + ‬6179J + 187.8J = 9086.3J

learn more:

Specific heat brainly.com/question/7210400

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