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gtnhenbr [62]
3 years ago
11

ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements.

Physics
1 answer:
vekshin13 years ago
6 0

Answer:

The answer is 500

Explanation:

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A damped harmonic oscillator consists of a mass on a spring, with a small damping force that is proportional to the speed of the
exis [7]

Answer:

2.19 N/m

Explanation:

A damped harmonic oscillator is formed by a mass in the spring, and it does a harmonic simple movement. The period of it is the time that it does one cycle, and it can be calculated by:

T = 2π√(m/K)

Where T is the period, m is the mass (in kg), and K is the damping constant. So:

2.4 = 2π√(0.320/K)

√(0.320/K) = 2.4/2π

√(0.320/K) = 0.38197

(√(0.320/K))² = (0.38197)²

0.320/K = 0.1459

K = 2.19 N/m

4 0
3 years ago
One description of the potential energy of a diatomic molecule is given by the Lennard-Jones potential,U =A/r¹² - B/r⁶ where A a
Andrei [34K]
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3 0
2 years ago
What is the function of the labeled structures?<br><br> A: <br><br> B: <br><br> C:
poizon [28]

Answer:

A: receives information

B: Carries information away from the cell body

C: Delivers information to the next cell

Explanation:

4 0
3 years ago
Read 2 more answers
Plz help on this ASAP !!
makkiz [27]

It would most likely be answer B considering the other ones don’t make sense in this question

4 0
3 years ago
In designing a backyard water fountain, a gardener wants to stream of water to exit from the bottom of one tub and land in a sec
mote1985 [20]

To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description.

From the definition we know that the speed of a body can be described as a function of gravity and height

V = \sqrt{2gh}

V = \sqrt{2*9.8*0.15}

V = 1.714m/s

Then applying the kinematic equation of displacement, the height can be written as

H = \frac{1}{2}gt^2

Re-arrange to find t,

t = \sqrt{2\frac{h}{g}}

t = \sqrt{2\frac{0.5}{9.8}}

t = 0.3194s

Thus the calculation of the displacement would be subject to

x = vt

x =1.714*0.3194

x = 0.547m

Therefore the required distance must be 0.547m

4 0
3 years ago
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