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Alina [70]
3 years ago
6

A tennis player smashes a ball of mass m horizontally at a vertical wall. The ball rebounds at the same speed v with which it st

ruck the wall. Has the momentum of the ball changed, and if so, by how much?
Physics
1 answer:
jeka57 [31]3 years ago
3 0

Answer:

The magnitude of change in momentum is (2mv).

Explanation:

The momentum of an object is given by the product of mass and velocity with which it is moving.

Let the mass of ball is m. A tennis player smashes a ball of mass m horizontally at a vertical wall. The ball rebounds at the same speed v with which it struck the wall.

Initial speed of the ball is v and final speed, when it rebounds, is (-v). The change in momentum is given by :

p = final momentum - initial momentum

p=-mv-mv\\\\p=-2mv

So, the magnitude of change in momentum is (2mv).

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Answer:

yes

Explanation:

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A heat engine cycle is executed with steam in the saturation dome. The pressure of steam is 1.1 MPa during heat addition and 0.3
klio [65]

Answer:The highest possible efficiency of this heat engine is 11%

Explanation:

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Saturated water temperature at  P2, Pressure in Heat rejection,

0.3MPa=133.5°C+ 273=406.5K

The highest possible efficiency of any heat engine is the Carnot efficiency given as

Carnot efficiency,  ηmax = 1- (T2/ T1)

1- (406.5K/458K)

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2 years ago
A friction force of 280 N exists between a cart and the path. If the force of reaction is 766 N, what is the minimum action forc
MatroZZZ [7]

force of friction on the cart is given as

F_f = 280 N

here we also know the reaction force due to surface

R = 766 N

so we can say reaction force is given as

R = \sqrt{F_n^2 + F_f^2}

766 = \sqrt{F_n^2 + 280^2}

F_n^2 = 766^2 - 280^2

F_n = 713 N

now by force balance we will say

F_y + F_n = mg

F_y = mg - F_n

F_x = F_f

also we know that

F_f = \mu * F_n

280 = \mu * 713

\mu = 0.39

now minimum force required to set this into motion

F_{min} = \frac{\mu mg}{\sqrt{1 + \mu^2}}

here we know that

mg = F_n = 713 N

F_{min} = \frac{0.39* 713}{\sqrt{1 + 0.39^2}}

F_{min} = 259 N

So it will require 259 N minimum force to move it

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3 years ago
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Answer:

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3 years ago
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