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irinina [24]
3 years ago
7

How many joules of heat are removed from a 21.0 g sample of water if it is cooled from 34.0°C

Chemistry
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

527.184 J of heat is removed from a 21 g water sample if it is cooled from 34.0 ° C to 28.0 ° C.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

When the heat added or removed from a substance causes a change in temperature in it, this heat is called sensible heat.

In other words, the sensible heat of a body is the amount of heat received or transferred by a body when it undergoes a change in temperature without there being a change in physical state (solid, liquid or gaseous). The equation that allows to calculate this heat exchange is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT=Tfinal-Tinitial is the change in temperature.

In this case:

  • c= 4.184 \frac{J}{g*C}
  • m=21 g
  • ΔT=Tfinal-Tinitial=28 °C - 34 °C=-6 °C

Replacing:

Q= 4.184 \frac{J}{g*C} * 21 g* (-6 C)

Q= - 527.184 J

To lower the temperature, heat has to be given, for that the final temperature must be lower than the initial temperature; and it receives the name of transferred heat and has a negative value, as in this case.

<u><em> 527.184 J of heat is removed from a 21 g water sample if it is cooled from 34.0 ° C to 28.0 ° C.</em></u>

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Sergio039 [100]

Answer:

1.21 times

Explanation:

The energy of a wave is proportional to the square of the amplitude of the wave.

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E\propto A^2

where

E is the energy of the wave

A is its amplitude

In this problem, the amplitude of the wave increases by a factor of 1.1; it means that the new amplitude can be written as

A'=1.1 A

Therefore, this means that the energy of the wave increases by a factor:

E'\propto A'^2=(1.1 A)^2 = 1.1^2 A^2 =1.21 A^2 = 1.21 E

Therefore, the energy of the wave increases by a factor 1.21.

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3 years ago
Can you find a salmander in the desert or rainforest?
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1. If 80.0 ml of 3.00 M HCl is used to make a 100. ml of dilute acid, what is the molarity
Aleonysh [2.5K]

<u>We are given:</u>

M1 = 3 Molar        V1 = 80 mL

M2 = x Molar        V2 = 100 mL

<u>Finding the molarity:</u>

We know that:

M₁V₁ = M₂V₂

where V can be in any units

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3 0
2 years ago
An electrochemical cell has the following standard cell notation: Al(s) | Al3+(aq) || Mg2+(aq) | Mg(s)
Soloha48 [4]

Answer:

a. Al(s) ⇄ Al⁺³(aq) + 3e⁻ (oxidation)

Mg²⁺(aq) + 2e⁻ ⇄ Mg(s) (reduction)

b. ΔE° = + 0.715 V

c.  It's an electrolytic cell, because it's a nonspontaneous reaction.

d. 2Al(s) + 3Mg²⁺(aq) ⇄ 2Al⁺³(aq) + 3Mg(s)

Explanation:

a. By the notation given, first is represented the oxidation reaction and then the reduction reaction, so they are:

Al(s) ⇄ Al⁺³(aq) + 3e⁻ (oxidation)

Mg²⁺(aq) + 2e⁻ ⇄ Mg(s) (reduction)

b. The standard potential of the cell (ΔE°) is the reduction potential of the oxidation less the reduction potential of the reduction. The reduction potentials are:

Al(s) = -1.66 V

Mg(s) = -2.375 V

ΔE° = -1.66 - (-2.375)

ΔE° = + 0.715 V

c. It's an electrolytic cell.

A galvanic cell is spontaneous, so the cathode (reduction) has a higher E° than the cathode (oxidation). In this case, the oxidation reaction has a higher E°, so the reaction is nonspontaneous and it's necessary an external force to it happen, so it's an electrolytic cell.

d. 2Al(s) + 3Mg²⁺(aq) ⇄ 2Al⁺³(aq) + 3Mg(s)

The number of electrons must be the same, so the oxidation reaction is multiplied by 2, and the reduction reaction by 3.

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3 years ago
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aliya0001 [1]
Cause limestone breaks down dirt and stone

7 0
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