Question

A double slit interference experiment is performed with blue -green light from an argon-gas laser. The separation between sits is 0.50 mm,and the first order maximum of the interference pattern is at an Angle of 0.059 degrees from the center of the pattern. What is the wavelength of the argon laser light

Answer 1

Answer:

The  wavelength of the argon laser light is = 5.15 × $10^{-4}$ mm

Explanation:

Separation between slits d = 0.5 mm

Angle $\theta$ = 0.059 °

Order of fringes m = 1

We know that

d $\sin\theta$ = m $\lambda$ ------ (1)

Put all the values in above formula

0.5 ( $\sin0.059$ ) = 1 × $\lambda$

0.5 × 0.00103 = 1 × $\lambda$

$\lambda$ = 5.15 × $10^{-4}$ mm

Therefore the  wavelength of the argon laser light is = 5.15 × $10^{-4}$ mm