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3 years ago

What is the name for C2H3OH

Chemistry

2 answers:

Leona [35]3 years ago

7 0

Molar mass of C2H3OH is 44.0526 g/mol

Nuetrik [128]3 years ago

5 0

Ethenol. Which has a molor mass of 44.05 g/mol

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What is a product in a chemical reaction?

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3 years ago

Help please! worth 100 points!

IRINA_888 [86]

Answer:

THIS IS ONLY WORTH 50 POINTS LIAR LOL

Explanation:

BUT ILL DO IT ANYWAY GIVE ME A SEC

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3 years ago

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Which of the following is the correct unit for molarity? mol/L L/mol g/mol mol × L

Tems11 [23]

mol/L

Molarity indicates the number of moles of solute per liter of solution.

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3 years ago

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Which type of atom has the strongest attraction for electrons in bond formation ba cl I Sr.

Nutka1998 [239]

The atom with the strongest attraction for electrons in bond formation is the atom with the most positive charge since an electron has a negative charge. Unlike attracts like. Among these, Sr and ba has 2+ and has the greatest charge but ba has a stronger electron affinity (decreasing from top to bottom). answer is barium.

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3 years ago

2NaOH + H2SO4 ------> 2 H2O + Na2SO4

balandron [24]

$\huge\fbox{Answer ☘}$

It is given in the question that 200.0 grams of sodium hydroxide reacts with excess of sulphuric acid.

The given reaction is shown below

$\bold\blue{2NAOH + H _{2}SO _{4} \: - > 2H _{2} O+ NA _{2}SO_{4} }\\$

In this reaction, two mole of sodium hydroxide react with one mole of sulphuric acid to give two mole of water and one mole of sodium sulfate.

To determine the mass of sodium sulfate, first calculate the moles of sodium hydroxide as the value of mass is provided.

The molecular weight of NaOH is 40 g/mol.

The formula is shown below.

$\pink{n = \frac{m}{ M}}\\$

Where,

✫ n is the number of moles

✫ m is the mass

✫ M is the molecular weight

To calculate the number of moles, substitute the values in the above equation.

$\pink{n = \frac{200.0}{40g \: mol {}^{ - 1} } } \\ \\\pink{ ⇢n = 5}$

In the equation it is given that 2 mole of sodium hydroxide gives 1 mole of sodium sulphate.

So, to determine the actual mole of sodium sulfate divide the calculated moles of NaOH by 2.

$\pink{⇢ \frac{5}{2}} \\ \\ \pink{⇢ 2.5 \: mol}$

So 2.5 mol sodium sulfate is formed from 5 mol NaOH.

The molecular weight of sodium sulfate is 142.1 g/mol.

To calculate the mass of sodium sulfate, substitute the values in the formula.

$\pink{⇢2.5 = \frac{m}{142.1g \: mol {}^{ - 1} } } \\ \\\pink{ ⇢ m = 2.5 \times 142.1 }\\ \\ \pink{⇢ m = 355.25}$

Therefore, the mass of sodium sulfate formed when we start with 200.0 grams of sodium hydroxide and you have excess sulphuric acid is 355.25g.

hope helpful~

5 0

2 years ago