Answer:
A) Adult cells are larger than those in a child.
Explanation:
Fully-grown adults are much larger in size than young children.
The potential energy decreases as kinetic energy increases. Hence, option C is correct.
<h3>What is potential energy?</h3>
Potential energy is stored energy that depends upon the relative position of various parts of a system.
To shoot an arrow, the string has to be released. The kinetic energy is converted by the potential energy of the bow. Therefore, potential energy is converted into kinetic energy.
Hence, option C is correct.
Learn more about the potential energy here:
brainly.com/question/24284560
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Answer:
7628 y
Explanation:
Carbon-14 is radioactive and it follows the first-order kinetics for a radioactive decay. The first-order kinetics may be described by the following integrated rate law:
![ln(\frac{[A]_t}{[A]_o})=-kt](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B%5BA%5D_t%7D%7B%5BA%5D_o%7D%29%3D-kt)
Here:
![[A]_t](https://tex.z-dn.net/?f=%5BA%5D_t)
is the mass, moles, molarity or percentage of the material left at some time of interest t;
![[A]_o](https://tex.z-dn.net/?f=%5BA%5D_o)
is the mass, moles, molarity or percentage of the material initially, we know that initially we expect to have 100 % of carbon-14 before it starts to decay;
is the rate constant;
is time.
The equation becomes:
![ln(\frac{[A]_t}{[A]_o})=-\frac{ln(2)}{T_{\frac{1}{2}}}t](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B%5BA%5D_t%7D%7B%5BA%5D_o%7D%29%3D-%5Cfrac%7Bln%282%29%7D%7BT_%7B%5Cfrac%7B1%7D%7B2%7D%7D%7Dt)
Given:
![\frac{[A]_t}{[A]_o} = \frac{40.0 %}{100.0 %}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5D_t%7D%7B%5BA%5D_o%7D%20%3D%20%5Cfrac%7B40.0%20%25%7D%7B100.0%20%25%7D)
Solve for time:
![t = -\frac{ln(\frac{[A]_t}{[A]_o})\cdot T_{\frac{1}{2}}}{ln(2)}](https://tex.z-dn.net/?f=t%20%3D%20-%5Cfrac%7Bln%28%5Cfrac%7B%5BA%5D_t%7D%7B%5BA%5D_o%7D%29%5Ccdot%20T_%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7Bln%282%29%7D)
In this case:
HCH bond angle is ~110 degrees.
Food that contains nuts should be prepared last
