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stich3 [128]
2 years ago
15

What would the color of this star cluster appear to be if you observed it from a distance so great that you could not make out t

he individual stars? What would the color of this star cluster appear to be if you observed it from a distance so great that you could not make out the individual stars?
A. green
B. violet
C. red
D. blue
Physics
1 answer:
makkiz [27]2 years ago
4 0

Answer:

D. blue

Explanation:

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6. An excited dog runs full-speed toward his owner who has just returned home from
mixas84 [53]

Answer:

v = 8.65 m/s

Explanation:

Given that,

Distance covered by the doge, d = 45 m

Time taken, t = 5.2 s

We need to find its average speed. The total distance covered divided by the total time taken is called the average speed of an object. So,

v=\dfrac{45\ m}{5.2\ s}\\\\=8.65\ m/s

So, the average speed is 8.65 m/s.

4 0
2 years ago
Sanjay is making plans for his Saturday afternoon. He can choose a health-enhancing activity like lifting weights, or he can cho
Bezzdna [24]

Answer: Sanjay can burn 100 more calories every 30 minutes if he chooses to lift weights instead of watching tv

Explanation: 133-33= 100 calories (says in article and i just answered it)

7 0
3 years ago
Friction is a ____________ force<br> a. Artificial<br> b. Natural<br> c. Pessimistic<br> d. Negative
Daniel [21]

Answer:

natural is the answer

5 0
2 years ago
Read 2 more answers
A tangent line drawn on a velocity-time graph has a rise of 19 m/s and a run of 4.0 m/s. How large is the acceleration? What typ
klemol [59]

Answer:

Acceleration = 4.8 m/s²

Explanation:

Given:

Change in velocity = 19 m/s

Change in time = 4 s

Find:

Acceleration

Computation:

Acceleration = Change in velocity / Change in time

Acceleration = 19/4

Acceleration = 4.8 m/s²

Positive acceleration

8 0
3 years ago
A baseball has mass 0.147 kg. If the velocity of a pitched ball has a magnitude of 44.5 m/s and the batted ball's velocity is 55
Anit [1.1K]

Explanation:

We have,

Mass of a baseball is 0.147 kg

Initial velocity of the baseball is 44.5 m/s

The ball is moved in the opposite direction with a velocity of 55.5 m/s

It is required to find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Change in momentum,

\Delta p=mv-mu\\\\\Delta p=m(v-u)\\\\\Delta p=0.147\times ((-55.5)-44.5)\\\\\Delta p=-14.7\ kg-m/s\\\\|\Delta p|=14.7\ kg-m/s

Impulse = 14.7 kg-m/s

Therefore, the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat is 14.7 kg-m/s

4 0
2 years ago
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