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Oksi-84 [34.3K]
1 year ago
12

A 100-m long transmission cable is suspended between two towers. If the mass density is 2. 01 kg/m and the tension in the cable

is 7. 30 × 10^3n. What is the speed of transverse waves on the cable?
Physics
1 answer:
lesya692 [45]1 year ago
3 0

The speed of transverse waves on the cable is 60.26 m/s.

Given,

μ=2.01kg/m, L=100m, T=7. 30 * 10^3N

Speed(v)=\sqrt{\frac{T}{μ} }=\sqrt{\frac{7.3*10^{3} }{2.01} }=60.26m/s

<h3>Speed</h3>

The speed of an object, sometimes known as "v" in daily speech and kinematics, is a scalar quantity that measures how much its position changes over time or how much it changes per unit of time. The distance traveled by an object during a time interval is equal to the duration of the interval divided by the object's speed, with the instantaneous speed being the upper limit of the average speed as the interval's duration becomes closer to zero. Velocity differs from speed.

Distance divided by time is the formula for measuring speed. A metre per second (m/s) is the metric unit of speed.

Learn more about speed here:

brainly.com/question/7359669

#SPJ4

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To determine an athlete's body fat, she is weighed first in air and then again while she's completely underwater. it is found th
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The difference in weight is due to the displacement of water (the buoyancy of water is acting on the athlete thus giving her smaller weight).<span>

The amount of weight displaced or the amount of buoyant force is: </span>

Fb = 690 N - 48 N

Fb = 642 N

From newtons law, F = m*g. Using this formula, we can calculate for the mass of water displaced:

m of water displaced = 642N / 9.8m/s^2

m of water displaced = 65.5 kg

Assuming a water density of 1 kg/L, and using the formula volume = mass/density:

V of water displaced = 65.5kg / 1kg/L = 65.5 L

The volume of water displaced is equal to the volume of athlete. Therefore:

V of athlete = 65.5 L

The mass of athlete can also be calculated using, F = m*g

m of athlete = 690 N/ 9.8m/s^2

m of athlete = 70.41 kg

 

Knowing the volume and mass of athlete, her average density is therefore:

average density = 70.41 kg / 65.5 L

<span>average density = 1.07 kg/L = 1.07 g/mL</span>

5 0
3 years ago
Read 2 more answers
How large a band of frequencies does each television broadcasting channel get ?
k0ka [10]

Answer:

Since the waves must carry a great deal of visual as well as audio information, each channel requires a larger range of frequencies than simple radio transmission. TV channels utilize frequencies in the range of 54 to 88 MHz and 174 to 222 MHz. (The entire FM radio band lies between channels 88 MHz and 174 MHz.)

8 0
3 years ago
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The boom is supported by the winch cable that has a diameter of 0.5 in. and allowable normal stress of σallow=21 ksi. A boom ris
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Explanation:

Let us assume that forces acting at point B are as follows.

        \sum F_{x} = 0

        T + F_{AB} Sin 60 = 0 ...... (1)

       \sum F_{y} = 0

       F_{AB} Cos 60 + W = 0 .......... (2)

Hence, formula for allowable normal stress of cable is as follows.

               \sigma_{allow} = \frac{T}{A}

       T = (20 \times 1000) \frac{\pi}{4} \times (0.5)^{2}

          = 3925 kip

From equation (1),   F_{AB}Sin (60^{o})  = -3925

               F_{AB} \times -0.304 8 = -3925

             F_{AB} = 12877.29 kip

From equation (2),    -12877.29 (Cos 60) + W = 0

         -12877.29 kip \times \frac{1}{2} + W = 0

                           W = 6438.64 kip

Thus, we can conclude that greatest weight of the crate is 6438.64 kip.

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How do land and sea breeze work?
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 by the wind and air flow in the wind

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An elevator (mass 4125 kg) is to be designed so that the maximum acceleration is 0.0400g.
fiasKO [112]
The way to do this is very easy so do 4125 x 2 = ? then the ? will be times by 2 again after the answer to both of those is your answer!!!
8 0
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