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snow_tiger [21]
3 years ago
10

Provide at least three examples of kinetic energy and potential energy. Then, identify where the energy is in each system you de

scribe and whether or not it is being converted. If it is being converted, identify how and into what. If it isn't, identify what is necessary for it to be.
Physics
1 answer:
dem82 [27]3 years ago
5 0

Kinetic energy:

1) A car traveling down the road has less kinetic energy than a semi-truck and traveling at the same speed because the car's mass is much less than the truck's.

2) A river flowing at a certain speed possesses kinetic energy because the water has a certain mass and it also has velocity.

3) An insect flying has a small amount of kinetic energy because its mass and velocity are relatively small.

Potential Energy:

1) The food we eat has chemical potential energy because as our body digests it, it provides us with energy for basic metabolism.

2) A stretched spring in a pinball machine has elastic potential energy and can move the steel ball when released.

3) When a crane swings a wrecking ball up to a certain height, it gains more potential energy and has the ability to crash through buildings.

You might be interested in
Why dose the moon appear to move frome the east to the west in the night sky?
Gala2k [10]

Answer:

Because Earth rotates on its axis from west to east

Explanation:

5 0
3 years ago
Red Riding Hood sat down to rest and placed her 1.20-kg basket of goodies beside her. A wolf came along, spotted the basket, and
anygoal [31]

Answer:

  117.6°

Explanation:

The vertical component of a force directed at some angle α from the vertical is ...

  F·cos(α)

We want the vertical components of the wolf's force (Fw) and Red's force (Fr) to total zero. So for some angle from vertical α, Red's force will satisfy ...

  Fw·cos(25°) + Fr·cos(α) = 0

  cos(α) = -Fw/Fr·cos(25°) ≈ -(6.4 N)/(12.5 N)·0.906308 ≈ -0.464030

  α ≈ arccos(-0.464030) ≈ 117.6°

Red was pulling at an angle of about 117.6° from the vertical.

_____

<em>Additional comment</em>

That's about 27.6° below the horizontal.

3 0
3 years ago
I need hlep please help a brother out
SCORPION-xisa [38]

Answer:

a

Explanation:

4 0
3 years ago
Two small objects each with a net charge of +Q exert a force of magnitude F on each other. We replace one of the objects with an
Alona [7]

Answer:

F'= 4F/9

Explanation:

Two small objects each with a net charge of +Q exert a force of magnitude F on each other. If r is the distance between them, then the force is given by :

F=\dfrac{kQ^2}{r^2} ...(1)

Now, if one of the objects with another whose net charge is + 4Q is replaced and also the distance between +Q and +4Q charges is increased 3 times as far apart as they were. New force is given by :

F'=\dfrac{kQ\times 4Q}{(3r)^2}\\\\F'=\dfrac{4kQ^2}{9r^2}.....(2)

Dividing equation (1) and (2), we get :

\dfrac{F}{F'}=\dfrac{\dfrac{kQ^2}{r^2}}{\dfrac{4kQ^2}{9r^2}}\\\\\dfrac{F}{F'}=\dfrac{kQ^2}{r^2}\times \dfrac{9r^2}{4kQ^2}\\\\\dfrac{F}{F'}=\dfrac{9}{4}\\\\F'=\dfrac{4F}{9}

Hence, the correct option is (d) i.e. " 4F/9"

7 0
3 years ago
A 2 kg object traveling at 5 m s on a frictionless horizontal surface collides head-on with and sticks to a 3 kg object initiall
Svetlanka [38]

Answer: (d)

Explanation:

Given

Mass of object m=2\ kg

Speed of object u=5\ m/s

Mass of object at rest M=3\ kg

Suppose after collision, speed is v

conserving momentum

\Rightarrow mu+0=(m+M)v\\\\\Rightarrow v=\dfrac{2\times 5}{2+3}\\\\\Rightarrow v=2\ m/s

Initial kinetic energy

k_1=\dfrac{1}{2}\times 2\times 5^2\\\\k_1=25\ J

Final kinetic energy

k_2=\dfrac{1}{2}\times (2+3)\times 2^2\\\\k_2=10\ J

So, it is clear there is decrease in kinetic energy . Thus, energy decreases and velocity becomes 2 m/s.

4 0
3 years ago
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