You just pointed out that the gravitational force also depends
on the distance from the planet's center. The radius of Uranus
is about 4 times the Earth's radius. That fact alone means that
the gravitational force on the surface is 1/4² = 1/16 its value on
Earth's surface. So increasing the planet's mass by a factor of
14 doesn't compensate for the 1/16 reduction, and the gravitational
force on Uranus is less than on Earth.
Answer:
9ms^2
Explanation:
since ,Force=mass*acceleration
then, acceleration=force/mass
and, Force=90N
Mass=10pound
therefore, acceleration=90/10
=9ms^2
<span>The
kinetic energy is the work done by the object due to its motion. It is
represented by the formula of the half the velocity squared multiply by the
mass of the object. In this problem, you have two vehicles, the other one is large and the
other one is small. Let us assume that they travel with the same velocity. Note
that the kinetic energy is proportional to the mass of the object. So when you
increase the mass of the other, it also increases the kinetic energy of that
object. The same holds true for the two vehicles. The larger the vehicle, its
kinetic energy is also large and therefore its stopping distance will be longer
than that of the smaller vehicle.</span>
The magnitude of the average force exerted on the ball by the wall is calculated below.
The average force exerted by the ball on the wall is 3 N
Explanation:
Given:
mass of the ball (m)=0.10 kg
speed (v) =3.0 m/s
time taken(t) =0.01 seconds
To calculate:
Average force(F) exerted by ball on the wall
We know;
F=(m×v)÷t
F=(0.10×3.0)÷0.01
<u><em>F=3 N</em></u>
Therefore the average force exerted by the ball on the wall is 3 N
Answer:F = kq2/d2 ⇒
q = √(Fd2/k)
q = d √(F/k)
d = 3.8 x 10-10 m
F = 6.4 x 10-9 N
Look up k in your physics book in appropriate units, and plug in the numbers. You should get q in coulombs.
Explanation:
