In a double-slit experiment, the distance from one slit to the m = 3 bright fringe is 2,000,198.2λ. What is the distance from th
1 answer:
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Answer:
Speed of another player, v₂ = 1.47 m/s
Explanation:
It is given that,
Mass of football player, m₁ = 88 kg
Speed of player, v₁ = 2 m/s
Mass of player of opposing team, m₂ = 120 kg
The players stick together and are at rest after the collision. It shows an example of inelastic collision. Using the conservation of linear momentum as :
V is the final velocity after collision. Here, V = 0 as both players comes to rest after collision.
So, the speed of another player is 1.47 m/s. Hence, this is the required solution.
Answer:
3. µs g /7
Explanation:
The largest Force appear when the maximal friction Force is required.
Second Newton law for the small block:
Second Newton law for the Big Block: