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Andrews [41]
4 years ago
5

A bucket of mass M (when empty) initially at rest and containing a mass of water is being pulled up a well by a rope exerting a

steady force P. The water is leaking out of the bucket at a steady rate such that the bucket is empty after a time T. Find the velocity of the bucket at the instant it becomes empty. Express your answer in terms of P, M, m, T, and g, the acceleration due to avily. Constant Rate Leak"
Physics
1 answer:
Naily [24]4 years ago
6 0

Answer:

V=\dfrac{PT}{m}\ ln\dfrac{M+m}{M}-gT

Explanation:

Given that

Constant rate of leak =R

Mass at time T ,m=RT

At any time t

The mass = Rt

So the total mass in downward direction=(M+Rt)

Now force equation

(M+Rt) a =P- (M+Rt) g

a=\dfrac{P}{M+Rt}-g

We know that

a=\dfrac{dV}{dt}

\dfrac{dV}{dt}=\dfrac{P}{M+Rt}-g

\int_{0}^{V}V=\int_0^T \left(\dfrac{P}{M+Rt}-g\right)dt

V=\dfrac{P}{R}\ ln\dfrac{M+RT}{M}-gT

V=\dfrac{PT}{m}\ ln\dfrac{M+m}{M}-gT

This is the velocity of bucket at the instance when it become empty.

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g A mass of 2.0 kg traveling at 3.0 m/s along a smooth, horizontal plane hits a relaxed spring. The mass is slowed to zero veloc
dezoksy [38]

By the work-energy theorem, the total work done on the mass by the spring is equal to the change in the mass's kinetic energy:

<em>W</em> = ∆<em>K</em>

and the work done by a spring with constant <em>k</em> as it gets compressed a distance <em>x</em> is -1/2 <em>kx</em> ²; the work it does is negative because the restoring force of the spring points opposite the direction in which it's getting compressed.

So we have

-1/2 <em>k</em> (0.15 m)² = 0 - 1/2 (2.0 kg) (3.0 m/s)²

Solve for <em>k</em> to get <em>k</em> = 800 N/m.

8 0
4 years ago
What is it called when the right side of a design is reflected across a central axis and mirrored on the left side of the design
guapka [62]

Answer:

What is it called when the right side of a design is reflected across a central axis and mirrored on the left side of the design?

5 0
3 years ago
Hemoglobin (Hb) is the O2-carrying protein in our blood. Unlike myoglobin, it has four sites allowing it to bind up to four O2 m
bogdanovich [222]

Answer:

Yes, the energy is not simply the sum of the individual binding energies at each site, it is the product of energy at each binding site of hemoglobin.

Explanation:

Myoglobin and hemoglobin are two different cells. Myoglobin binds only one oxygen while the hemoglobin has the ability to binds four oxygen atoms at its four sides. Myoglobin present in muscle tissue only while hemoglobin is present in the whole body. Oxyhemoglobin is formed when oxygen binds with hemoglobin cell. This oxygen is take to all cells and energy is released due to the breakdown of glucose molecules with this oxygen.

4 0
4 years ago
David rowed a boat upstream for three miles and then returned to point he started from. The entire journey took four hours. The
frez [133]
Upstream speed = S - 1
Downstream speed = S + 1

Average speed = total distance / total time

Average speed = (S - 1) + (S + 1) / 2
= S

S = 6 miles / 4 hours
S = 1.5 miles per hour
4 0
3 years ago
If homeboy joe is pushing a box with force of 57.0 in the horizontal direction and -15.0 in the vertical direction. What is the
Ksenya-84 [330]

Answer:

The magnitude of joes net force is 58.9.

Explanation:

The magnitude of the net force is given by:

F_{net} = \sqrt{F_{x}^{2} + F_{y}^{2}}

Where:

F_{x}: is the force in the horizontal direction = 57.0

F_{y}: is the force in the vertical direction = -15.0

F_{net} = \sqrt{(57.0)^{2} + (-15.0)^{2}} = 58.9

Therefore, the magnitude of joes net force is 58.9.

I hope it helps you!                                                                                        

5 0
3 years ago
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