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jonny [76]
3 years ago
12

You sit at the middle of a large turntable at an amusement park as it is set spinning on nearly frictionless bearings, and then

allowed to spin freely. When you crawl toward the edge of the turntable, does the rate of the rotation increase, decrease, or remain unchanged, and why
Physics
1 answer:
jolli1 [7]3 years ago
3 0

Answer:

Decrease

Explanation:

If you crawl to the rim the rotational speed will decrease. The law of conservation of angular momentum supports this answer. And it states that :

"When the net external torque acting on a system about a given axis is. zero , the total angular momentum of the system about that axis remains constant."

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Some hydrogen gas is enclosed within a chamber being held at 200^\ { C} with a volume of 0.025 \rm m^3. The chamber is fitted wi
vlada-n [284]

Answer:

The final volume is 0.039 m^3

Explanation:

<u>Data:</u>

Initial temperature: T1=200C

Final temperature: T2=200C

Initial pressure: P1=1.50 \times10^6 Pa

Final pressure: P2=0.950 \times10^6 Pa

Initial volume: V1=0.025m^{3}

Final volume: V2=?

Assuming hydrogen gas as a perfect gas it satisfies the perfect gas equation:

\frac{PV}{T}=nR (1)

With P the pressure, V the volume, T the temperature, R the perfect gas constant and n the number of moles. If no gas escapes the number of moles of the gas remain constant so the right side of equation (1) is a constant, that allows to equate:

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

Subscript 2 referring to final state and 1 to initial state.

solving for V2:

V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}=\frac{(1.50 \times10^6)(0.025)(200)}{(200)(0.950 \times10^6)}

V_{2}=0.039 m^3

3 0
3 years ago
Scouts at a camp shake the rope bridge they have just crossed and observe the wave crests to be 8.00 m apart. If they shake it t
kaheart [24]

Answer:

Explanation:

distance between two crests = 8 m

The distance between the two crests is called wavelength.

So, wavelength, λ = 8 m

frequency = 2 Hz

Let v be the velocity of wave.

v = f x λ

v = 2 x 8

v = 16 m/s

8 0
3 years ago
It is 2058 and you are taking your grandchildren to Mars. At an elevation of 34.7 km above the surface of Mars, your spacecraft
Paul [167]

Answer: 1.23\ m/s^2

Explanation:

Given

At an elevation of y=34.7\ km, spacecraft is dropping vertically at a speed of u=293\ m/s

Final velocity of the spacecraft is v=0

using equation of motion i.e. v^2-u^2=2as

Insert the values

\Rightarrow 0-(293)^2=2\times a\times (34.7\times 10^3)\\\\\Rightarrow a=-\dfrac{293^2}{2\times 34.7\times 10^3}\\\\\Rightarrow a=-1.23\ m/s^2

Therefore, magnitude of acceleration is 1.23\ m/s^2.

8 0
2 years ago
NEEDD SOME HELP ASAP HELP MEHHH<br> 50 pOINTS
Vadim26 [7]
An electron shell can hold 2(n^2) electrons (technically) where n is the shell number, i.e. shell 1 can hold 2, shell 2 can hold 8, 3 holds 18 and so on.
The atomic number of Nitrogen is 7, i.e. it has 7 electrons (to match its 7 protons, assuming it isn't an ion).

With the atomic number, you simply start from shell 1 and work out. So we put 2 electrons in shell 1, leaving us with 5 left. Shell 2 can hold 6 so we can fit all 5 in.

In other words, you should have 2 electron shells on the atom, shell 1 with 2 e- and shell 2 with 5 e-.
3 0
3 years ago
Read 2 more answers
A bowler throws a bowling ball of radius R = 11 cm down the lane with initial speed v₀ = 7.5 m/s. The ball is thrown in such a w
salantis [7]

Answer:

a) t = 0.74s

b) D = 4.76m

c) Vf = 5.35m/s

Explanation:

The ball starts rolling when Vf = ωf*R.

We know that:

Vf = Vo - a*t

ωf = ωo + α*t

With a sum of forces on the ball:

Ff = m*a

\mu*N = m*a

\mu*m*g = m*a

a=\mu*g=2.9m/s^2

With a sum of torque on the ball:

Ff*R = I*\alpha

\mu*m*g*R = 2/5*m*R^2*\alpha

\alpha=5/2*\mu*g/R=65.9rad/s^2

Replacing both accelerations:

Vo - a*t=\alpha*t*R

7.5 - 2.9*t=65.9*t*0.11

t=0.74s

The distance will be:

D = Vo*t-1/2*a*t^2

D = 4.76m

Final velocity:

Vf=Vo-a*t

Vf=5.35m/s

7 0
3 years ago
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