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Likurg_2 [28]
3 years ago
10

You add 500 mL of water at 10°C to 100 mL of water at 70°C. What is the

Physics
1 answer:
laiz [17]3 years ago
5 0

Answer:

20°C

Explanation:

Heat gained by the colder water = heat lost by the warmer water

m₁ C (T − T₁) = m₂ C (T₂ − T)

m₁ (T − T₁) = m₂ (T₂ − T)

(500) (T − 10) = (100) (70 − T)

5 (T − 10) = 70 − T

5T − 50 = 70 − T

6T = 120

T = 20

The final temperature is 20°C.

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Read 2 more answers
A spring with spring constant 33N/m is attached to the ceiling, and a 4.8-cm-diameter, 1.5kg metal cylinder is attached to its l
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Answer:

0.423m

Explanation:

Conversion to metric unit

d = 4.8 cm = 0.048m

Let water density be \who_w = 1000 kg/m^3

Let gravitational acceleration g = 9.8 m/s2

Let x (m) be the length that the spring is stretched in equilibrium, x is also the length of the cylinder that is submerged in water since originally at a non-stretching position, the cylinder barely touches the water surface.

Now that the system is in equilibrium, the spring force and buoyancy force must equal to the gravity force of the cylinder. We have the following force equation:

F_s + F_b = W

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kx + \rho_w V_s g = mg

The submerged volume would be the product of cross-section area and the submerged length x

V_s = Ax = \pi(d/2)^2x

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kx + \rho_w \pi(d/2)^2x g = mg

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x = \frac{m}{(k/g) + (\rho_w\pi d^2/4)} = \frac{1.5}{(33/9.8) + (100*\pi * 0.048^2/4)} = 0.423 m

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