You add 500 mL of water at 10°C to 100 mL of water at 70°C. What is the
1 answer:
Answer:
20°C
Explanation:
Heat gained by the colder water = heat lost by the warmer water
m₁ C (T − T₁) = m₂ C (T₂ − T)
m₁ (T − T₁) = m₂ (T₂ − T)
(500) (T − 10) = (100) (70 − T)
5 (T − 10) = 70 − T
5T − 50 = 70 − T
6T = 120
T = 20
The final temperature is 20°C.
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