Answer:
The temperature rise of the water is = 0.14 °c
Explanation:
Height = 60 m
Potential energy change ΔP =
ΔP = m × 9.81 × 60
ΔP = (588.6 × m) Joule
Since the Potential energy change is equal to the internal energy change or Enthalpy change.
ΔP = ΔH
Since ΔH = m × C × ΔT
⇒ ΔP = m × C × ΔT
Put all the values in above formula we get
⇒ 588.6 × m = m × 4184 × ΔT
⇒ ΔT= 0.14 °c
Therefore the temperature rise of the water is = 0.14 °c
The answer is 54.675 J
<span>The kinetic energy (Ke) of an object is the product of half of its mass (m) and the square of its velocity (v²):
</span>Ke = 1/2 m * v²
We have:
Ke = ?
m = 15 kg
v = 2.7 m/s
_____
Ke = 1/2 * 15 kg * (2.7 m/s)² = 1/2 * 15 kg * 7.29 m²/s² = 54.675 kg * m²/s²
Ke = 54.675 J
Answer:
Since the net force is to the right (in the direction of the applied force), then the applied force must be greater than the friction force. The friction force can be determined using an understanding of net force as the vector sum of all the forces.
Explanation:
Answer:
0.381 m
Explanation:
Distance traveled S is found by
Where S is distance traveled, u is initial velocity, t is time, a is acceleration
Since we acceleration a is given as 60g, where g is gravitational constant of 9.81 then a=60*9.81=588.6
The initial velocity u is zero hence ut=0
Substituting a with 588.6, t with 36 ms
S=0.381 m