Answer:
composition changes
Explanation:
The main difference between physical and chemical changes is the following:
- in a physical change, no new substances are formed, while the atoms/molecules of the original substances can be re-arranged. Examples of physical changes are the change of state (for instance, from solid to liquid): no new substance are formed, but the bonds between molecules are broken and the molecules change position/arrangement.
- in a chemical change, new substances are formed: an example of this change are chemical reaction, such as the burning of a substance, in which new substances are formed. For this reason, the composition changes during a chemical change.
Answer:
80 Meters.
Explanation:
What I did was took how many seconds the ball traveled and multiply how fast the ball was going. I actually do a lot of these questions. :))
May I please have brainlyest??
Apply this kinematics equation for the particle's vertical motion:
D = Vt + 0.5At²
D = vertical distance traveled, t = time, V = initial vertical velocity, A = vertical acceleration
Given values:
D = 49m
V = 34.3m/s
A = -9.81m/s²
Plug in and solve for t:
49 = 34.3t - 4.905t²
4.905t² - 34.3t + 49 = 0
Use the quadratic roots formula to find the values of t:
t ≈ 2, 5
The particle reaches a height of 49m at t = 2s & t = 5s
Answer:
![r=2.3808\ \Omega](https://tex.z-dn.net/?f=r%3D2.3808%5C%20%5COmega)
Explanation:
Given:
- power of battery,
![P_b=16.2\ W](https://tex.z-dn.net/?f=P_b%3D16.2%5C%20W)
- voltage across the load resistor,
![V=13.3\ V](https://tex.z-dn.net/?f=V%3D13.3%5C%20V)
- emf of the battery,
![emf=16.2\ V](https://tex.z-dn.net/?f=emf%3D16.2%5C%20V)
<u>Now as we know that the electric power is given as:</u>
![P_b=\frac{V^2}{R}](https://tex.z-dn.net/?f=P_b%3D%5Cfrac%7BV%5E2%7D%7BR%7D)
here:
resistance of the load
a)
Now the load resistance:
![R=\frac{V^2}{P_b}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7BV%5E2%7D%7BP_b%7D)
![R=\frac{13.3^2}{16.2}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B13.3%5E2%7D%7B16.2%7D)
![R=10.92\ \Omega](https://tex.z-dn.net/?f=R%3D10.92%5C%20%5COmega)
b)
Using Ohm's law, current in the load:
![I=\frac{V}{R}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7BV%7D%7BR%7D)
![I=\frac{13.3}{10.92}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B13.3%7D%7B10.92%7D)
![I=1.218\ A](https://tex.z-dn.net/?f=I%3D1.218%5C%20A)
Now,
![emf-V=r.I](https://tex.z-dn.net/?f=emf-V%3Dr.I)
where:
internal resistance
![16.2-13.3=r\times 1.218](https://tex.z-dn.net/?f=16.2-13.3%3Dr%5Ctimes%201.218)
![r=2.3808\ \Omega](https://tex.z-dn.net/?f=r%3D2.3808%5C%20%5COmega)
Answer:
60,000 kgm/s
Explanation:
momentum equation,
momentum = mass × velocity.
mass = 2000kg
velocity = 30m/s
when multipled you get = 60,000 kgm/s
hope it helps. :)