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NARA [144]
3 years ago
6

Consider the following class definitions: class smart class superSmart: public smart { { public: public: void print() const; voi

d print() const; void set(int, int); void set(int, int, int); int sum(); int manipulate(); smart(); superSmart(); smart(int, int); superSmart(int, int, int); private: private: int x; int z; int y; int secret(); }; }; Which private members, if any, of smart are public members of superSmart
Engineering
1 answer:
arsen [322]3 years ago
5 0

Answer:

a) There is no any private member of smart which are public members of superSmart.

Explanation:

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Anastasy [175]
Given data:
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We can find the relation ship between current, voltage and resistance with the help of Ohms law.

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Explanation:

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3 years ago
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allochka39001 [22]

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