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NARA [144]
3 years ago
6

Consider the following class definitions: class smart class superSmart: public smart { { public: public: void print() const; voi

d print() const; void set(int, int); void set(int, int, int); int sum(); int manipulate(); smart(); superSmart(); smart(int, int); superSmart(int, int, int); private: private: int x; int z; int y; int secret(); }; }; Which private members, if any, of smart are public members of superSmart
Engineering
1 answer:
arsen [322]3 years ago
5 0

Answer:

a) There is no any private member of smart which are public members of superSmart.

Explanation:

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The parts of a feature control frame are the tolerance value, the datum references, and the
Elan Coil [88]

Answer:

d

Explanation:

4 0
4 years ago
A circular bar is 800mm in length and 32mm in diameter. The bar is made from a material with a modulus of elasticity E = 150 GPa
Yuki888 [10]

Answer:

For any material if ∈ is the axial strain then the lateral strain is given by -μ∈ is the lateral strain in the object

Where,

μ is the poisson's ratio of the material

The longitudinal strain is calculated as follows

\varepsilon _{axial}=\frac{\Delta length}{Length_{original}}\\\\\therefore \varepsilon _{axial}=\frac{0.7}{800}=8.75\times 10^{-4}

Thus the lateral strain becomes

\varepsilon _{lateral}=-\mu\varepsilon _{axial}\\\\\varepsilon _{lateral}=-0.27\times 8.75\times 10^{-4}=-2.36\times 10^{-4}

now by definition of lateral strain we have

\varepsilon _{lateral}=\frac{\Delta diameter}{diameter_{original}}\\\\\Rightarrow \Delta Diameter=-2.36\times 10^{-4}\times 32=-7.56\times 10^{-3}\\\\D_{f}-D_{i}=-7.56\times 10^{-3}\\\\D_{f}=32-7.56\times 10^{-3}=31.992mm

By hookes law the stress developed due to the given strain is given by

\sigma =\varepsilon _{axial}E

Applying values we get

\sigma =8.75\times 10^{-4}\times 150\times 10^{9}\\\\\sigma =131.25MPa

Thus the force is calculated as

Force=\sigma \times Area\\\\Force=131.25\times 10^{6}\times \frac{\pi (32\times 10^{-3})^{4}}{4}\\\\Force=105.55kN

5 0
3 years ago
When a thin glass tube is put into water, the water rises 1.4 cm. When the same tube is put into hexane, the hexane rises only 0
VARVARA [1.3K]

Answer:

Due to differences in the nature of the adhesive force and cohesive forces in the molecules of the individual substances and the glass tube.

Explanation:

To understand why this is so, a deep understanding of adhesive and cohesive force is required.

First, what is adhesive force?

Note: Adhesive and cohesive forces are best discussed under macroscopic level.

Adhesive force is the Intermolecular forces that exist between atoms of different molecules e g the forces explain when unlike charges stick together.

Cohesive force on the other hand is the Intermolecular force that exist between atoms of the same molecules e.g the force between hydrogen bonding.

Hence to explain the case scenario above, the adhesive force between the water molecules and the glass molecules is higher than the cohesive force between the water molecules. Hence the high rise.

For the case of the Hexane, the cohesive forces between the molecules hexane is far greater then the adhesive force between the glass molecules and the hexane molecules.

7 0
3 years ago
What is the subtotal for the building materials in the bill? The subtotal should be the cost of the materials only. Don't add ta
Alexxx [7]

Answer:

Cost before adding taxes and incorporating variations

Explanation:

The sub-totals are basically sum of the cost from individual pages before including value added tax or any other tax depending with the state regulations. At this stage, contingencies and variation of prices are not considered. Therefore, the sub-total for building materials only include the materials on site or materials used as per the bill of quantities and certified by the engineer.

3 0
4 years ago
Some soil has a discharge rate of 0.1 L/s, an area of 11 m2, and a hydraulic head that is given empirically by the function H =
Artist 52 [7]

Answer:

3.03 * 10 ⁻⁴ m/s

Explanation:

see attached picture for explanation.

3 0
3 years ago
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