Question

Assume that Young’s modulus for a new material is known to be 2.25 × 1011 /2

Answer 1

Answer:

Maximum force, $F_{max} = 42 kN$

Explanation:

Maximum Stress, $\sigma_{max} = 2.1 * 10^{7} N/m^{2}$

The diameter of the material, d = 50.5 mm = 0.0505 m

The area of the material, $A = (\pi d^{2} )/4$

$A = \frac{\pi * 0.0505^{2} }{4} \\A = 0.002 m^{2}$

The formula for the maximum stress that the material can take is given by:

$\sigma_{max} = \frac{F_{max} }{A} \\2.1 * 10^7 = \frac{F_{max} }{0.002}\\F_{max} = 2.1 * 10^7 * 0.002\\F_{max} = 4.2 * 10^4 N\\F_{max} = 42 kN$