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ivolga24 [154]
3 years ago
12

I NEEED HELLPPP PLZZZZZ HELPPPP

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
6 0
I think it's nonmetals
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What is the maximum amount of ammonia that can be produced when 0.35 mol Nz reacts with 0.90 mol Hz?
professor190 [17]

Answer:

0.6 moles NH₃

Explanation:

The reaction that takes place is:

  • N₂ + 3H₂ → 2NH₃

First we <u>determine the limiting reactant</u>:

  • 0.35 mol N₂ would react completely with (3*0.35) 1.05 moles of H₂. There are not as many H₂ moles, so H₂ is the limiting reactant.

Then we <u>convert H₂ moles (the limiting reactant) to NH₃ moles</u>, keeping in mind the <em>stoichiometry of the reaction</em>:

  • 0.90 mol H₂ * \frac{2molNH_3}{3molH_2}= 0.6 moles NH₃

5 0
3 years ago
What do you know about Relative Dating
gizmo_the_mogwai [7]
<span>it tells you the sequence in which events occurred, not how long ago they occurred.</span>
8 0
3 years ago
In the relationship between ΔG and K for a given reaction, if ΔG is negative, what is K? K is equal to 0. K is equal to 1. K is
frutty [35]
K is greater than 1. #platolivesmatter
3 0
3 years ago
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What is the ph of a solution of 1.699 l of 1.25 m hcn, ka = 6.2 x 10-10, and 1.37 moles of nacn?
BlackZzzverrR [31]

The pH of a solution is 9.02.

c(HCN) = 1.25 M; concentration of the cyanide acid

n(NaCN) = 1.37 mol; amount of the salt

V = 1.699 l; volume of the solution

c(NaCN) = 1.37 mol ÷ 1.699 l

c(NaCN) = 0.806 M; concentration of the salt

Ka = 6.2 × 10⁻¹⁰; acid constant

pKa = -logKa

pKa = - log (6.2 × 10⁻¹⁰)

pKa = 9.21

Henderson–Hasselbalch equation for the buffer solution:

pH = pKa + log(cs/ck)

pH = pKa + log(cs/ck)

pH = 9.21 + log (0.806M/1.25M)

pH = 9.21 - 0.19

pH = 9.02; potential of hydrogen

More about buffer: brainly.com/question/4177791

#SPJ4

8 0
1 year ago
Which are examples of equilibrium? Check all that apply.
NeX [460]
The equilibrium means that amount that are coming equals the amount that are going.
So the correct answers are
<span>2. A person's income and expenses are equal every month.
</span><span>3. The pressure exerted on the inside of a balloon by the gas inside is equal to the pressure exerted on the outside of the balloon by the atmosphere.</span>
6 0
3 years ago
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