Answer:
True
Explanation:
If a question cannot be tested and observed, it cannot simply be answered by science.
Science works with observable and testable ideas and not on metaphysics.
- Science presents a methodical approach into investigating phenomenon and answering likely questions in a logical manner.
- The body of facts and data gathered through observations and tests are used to ramify the conclusion of a scientific study.
- Without such, it is impossible to do the work of science.
Answer:
a) ΔGrxn = 6.7 kJ/mol
b) K = 0.066
c) PO2 = 0.16 atm
Explanation:
a) The reaction is:
M₂O₃ = 2M + 3/2O₂
The expression for Gibbs energy is:
ΔGrxn = ∑Gproducts - ∑Greactants
Where
M₂O₃ = -6.7 kJ/mol
M = 0
O₂ = 0
![deltaG_{rxn} =((2*0)+(3/2*0))-(1*(-6.7))=6.7kJ/mol](https://tex.z-dn.net/?f=deltaG_%7Brxn%7D%20%3D%28%282%2A0%29%2B%283%2F2%2A0%29%29-%281%2A%28-6.7%29%29%3D6.7kJ%2Fmol)
b) To calculate the constant we have the following expression:
![lnK=-\frac{deltaG_{rxn} }{RT}](https://tex.z-dn.net/?f=lnK%3D-%5Cfrac%7BdeltaG_%7Brxn%7D%20%7D%7BRT%7D)
Where
ΔGrxn = 6.7 kJ/mol = 6700 J/mol
T = 298 K
R = 8.314 J/mol K
![lnK=-\frac{6700}{8.314*298} =-2.704\\K=0.066](https://tex.z-dn.net/?f=lnK%3D-%5Cfrac%7B6700%7D%7B8.314%2A298%7D%20%3D-2.704%5C%5CK%3D0.066)
c) The equilibrium pressure of O₂ over M is:
![K=P_{O2} ^{3/2} \\P_{O2}=K^{2/3} =0.066^{2/3} =0.16atm](https://tex.z-dn.net/?f=K%3DP_%7BO2%7D%20%5E%7B3%2F2%7D%20%5C%5CP_%7BO2%7D%3DK%5E%7B2%2F3%7D%20%3D0.066%5E%7B2%2F3%7D%20%3D0.16atm)
Answer:
theirs a $50 tax with the income hes making
Explanation:
Explanation:
9.0122 g be Maybe, sorry i don't think so
Slow it down - I believe?