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zmey [24]
3 years ago
7

Using what you have learned about the three forms of writing chemical equations, classify each of the presented equations as eit

her a molecular equation, a complete ionic equation, or a net ionic equation.
(a) Ca2+(aq) + SO42−(aq)→ CaSO4(s)
(b) CuSO4(aq) + 2KOH(aq)→ Cu(OH)2(s) + K2SO4(aq)
(c) Ba2+ (aq) + SO42−(aq)→ BaSO4(s)
(d) Ag+(aq) + NO3−(aq) + I−(aq)→ AgI(s) + NO3−(aq)
Chemistry
1 answer:
suter [353]3 years ago
3 0

Explanation:

Molecular equation: Chemical equation in which molecular formula of reactants and products are written

Complete ionic equation:Chemical equation in which ionic from if reactants reactants and products are written along with spectator ions (ions present on both sides of equation).

Net ionic equation :Chemical equation in which only ions of those reactant are written which giving product without  spectator ions (ions present on both sides of equation).

(a) Ca^{2+}(aq) + SO_4^{2-}(aq)\rightarrow CaSO_4(s)

net ionic equation.

(b) CuSO_4(aq) + 2KOH(aq)\rightarrow Cu(OH))_2(s) + K_2SO_4(aq)

Molecular equation

(c)Ba^{2+} (aq) + SO_4^{2-}(aq)\rightarrow BaSO_4(s)

Net ionic equation.

(d) Ag^+(aq) + NO_{3}^-(aq) + I^-(aq)\rightarrow AgI(s) + NO_{3}^-(aq)

Complete ionic equation

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Nataliya [291]

From the stoichiometry of the reaction, the mass of barium nitrate produced is 54.9 g.

<h3>Stoichiometry</h3>

The term stoichiometry refers to mass - volume relationships. Stoichiometry can be used to calculate the amount, mass or volume of reactants and products from the balanced reaction equation.

The equation of the reaction is written as follows;

BaCO3 + 2HNO3 ------>  Ba(NO3)2 + CO2 + H2O

Number of moles of BaCO3  = 55 g/197.34 g/mol = 0.28 moles

Number of moles of HNO3 = 26 g/63.01 g/mol = 0.41 moles

From the reaction equation;

1 mole of BaCO3 reacts with 2 moles of HNO3

0.28 moles of BaCO3 reacts with 0.28 moles ×  2 moles/1 mole = 0.56 moles

There is not enough HNO3 hence it is the limiting reactant.

Number of moles of Ba(NO3)2 produced  is obtained from;

2 moles of HNO3  yields 1 mole of Ba(NO3)2

0.41 moles of HNO3  yields 0.41 moles × 1 mole/2 moles

= 0.21 moles of Ba(NO3)2

Mass of  Ba(NO3)2  = 0.21 moles  × 261.337 g/mol = 54.9 g

Learn more about stoichiometry: brainly.com/question/9743981

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