The electronic configuration of Chlorine is 1s2 2s2 2p6 3s2 3p5.
There are three energy levels in chlorine
First energy level is n=1 has 1s2 so total 2 electrons
Second energy level is n=2, 2s2 2p6 so total 2+6= 8 electrons
Third has 3s2 3p5 electrons just 7 total... p can contain 6 electrons but only 5 are present. So the third level has lesser number of electrons than that can be filled
<span>I think the correct
answer is 109.5 degrees. The bond angle of a chlorite ion or ClO2- ion is 109.5
and has a bent shape. This is because of two groups of bonding electrons and
two lone pairs of electrons. Another example of a molecule that has a bent
molecular geometry is water. It results from its tetrahedral electron pair
shape.</span>
Answer:
0.00559 mol
Explanation:
The following data were obtained from the question:
V = 140mL = 0.14L
T = 296K
P = 98.2kPa = 98200Pa
Recall: 101325Pa = 1atm
98200Pa = 98200/101325 = 0.97atm
R = 0.082atm.L/Kmol
n =?
The number of mole (n) can be obtained as follows:
PV = nRT
n = PV /RT
n = (0.97x0.14)/(0.082x296)
n = 0.00559 mol
Therefore, the number of mole of the gas present is 0.00559 mol
Answer:-
,
, ![[CO_3^2^-]=0.254M](https://tex.z-dn.net/?f=%5BCO_3%5E2%5E-%5D%3D0.254M)
Solution:- We are asked to calculate the molarity of sodium carbonate solution as well as the sodium and carbonate ions.
Molarity is moles of solute per liter of solution. We have been given with 6.73 grams of sodium carbonate and the volume of solution is 250.mL. Grams are converted to moles and mL are converted to L and finally the moles are divided by liters to get the molarity of sodium carbonate.
Molar mass of sodium carbonate is 105.99 gram per mol. The calculations for the molarity of sodium carbonate are shown below:

= 
So, molarity of sodium carbonate solution is 0.254 M.
sodium carbonate dissociate to give the ions as:

There is 1:2 mol ratio between sodium carbonate and sodium ion. So, the molarity of sodium ion will be two times of sodium carbonate molarity.
= 0.508 M
There is 1:1 mol ratio between sodium carbonate and carbonate ion. So, the molarity of carbonate ion will be equal to the molarity of sodium carbonate.
![[CO_3^2^-]=0.254M](https://tex.z-dn.net/?f=%5BCO_3%5E2%5E-%5D%3D0.254M)
Answer:
C- private
Explanation:
This event seems to be exclusive. That is why it is private.