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saw5 [17]
3 years ago
9

sample of carbon monoxide gas occupies 3.20 L at 125 °C. At what temperature will the gas occupy a volume of 1.54 L if the press

ure remains constant?
Chemistry
2 answers:
Anna [14]3 years ago
3 0

Answer:

-81.5 degrees C or 191.5 K

Explanation:

We want to use Charles' gas law: V/T = V/T

Our initial volume is 3.20 L, and our initial temperature is 125 degrees C, or 125 + 273 = 398 degrees Kelvin.

Our new Volume is 1.54 L, but we don't know what the temperature is. So, we use the equation:

3.20 L / 398 K = 1.54 L / T ⇒ Solving for T, we get: T = 191.5 K

If we want this in degrees Celsius, we subtract 273: 191.5 - 273 = -81.5 degrees C

Sophie [7]3 years ago
3 0

Answer:

- 81.5°C

Explanation:

Data obtained from the question include:

V1 (initial volume) = 3.20 L

T1 (initial temperature) = 125 °C = 125 + 273 = 398K

V2 (final volume) = 1.54 L

T2 (final temperature) =.?

At constant pressure indicates that the gas is obeying Charles' law. Using the Charles' law equation V1/T1 = V2/T2 , the final temperature of the gas can be obtained as illustrated below:

V1/T1 = V2/T2

3.2/398 = 1.54/T2

Cross multiply to express in linear form

3.2 x T2 = 398 x 1.54

Divide both side by 3.2

T2 = (398 x 1.54)/ 3.2

T2 = 191.5K

Now let us convert 191.5K to celsius temperature. This is illustrated below

°C = K - 273

°C = 191.5 - 273

°C = - 81.5°C

Therefore the gas will occupy 1.54L at a temperature of - 81.5°C

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Draw the Lewis structures of the molecules below and use them to answer the following questions:
Gnesinka [82]

Answer:

If NO₂ molecule written is for Nitrogen dioxide, then, four of the five molecules presented above have no dipole moment and only one of the five molecules, Ozone (0₃), has a dipole moment.

But if the NO₂ molecule is for nitrite ion, NO₂⁻, then three out of the five molecules presented have no dipole moment and only the Nitrite ion, NO₂⁻, and Ozone, 0₃, have dipole moments.

Explanation:

- The Lewis Structure for the molecules are drawn in the image attached to this answer.

The bond dipole moment uses the idea of electric dipole moment to measure the polarity of a chemical bond within a molecule. It occurs whenever there is a separation of positive and negative charges. Polarity occurs due to differences in electronegativity.

1) Browne or Trihydridoboron, BH₃ - No dipole moment in the molecule.

Each B-H bond in BH₃ is polar/forms a dipole because the B and H atoms have different electronegativities. But, the shape of the molecule is trigonal planar which is symmetrical, so the dipoles/bond polarities cancel. The resulting BH₃ molecule is non-polar.

2)Nitrogen dioxide, NO₂ has no dipole moment.

Nitrite ion, NO₂⁻ -> Has a dipole moment.

There are two NO₂ molecules, the Nitrogen dioxide molecule is linear and has no dipole moment, but the NO₂⁻ ion is a polar molecule. The geometry of the molecule is bent because of a non-bonding pair of electrons. The bent geometry causes the polarity and subsequent dipole moment.

3) Sulfur hexafluoride, SF₆ - no dipole moment.

Sulfur hexafluoride, abbreviated as SF₆, is a nonpolar molecule. SF₆ has an octahedral molecular geometry, which means that the sulfur molecule has six fluorine atoms surrounding it. While each individual bond is polar, there is no net effect as symmetrical nature of this octahedral molecular structure means the dipole moments all cancel out, meaning that the molecule is nonpolar.

4) Ozone, O₃ - has a dipole moment.

O₃ is polar because there are 18 valence electrons, so the lewis structure would position the central O connected to one single bond and one double bond to connect the other O's. The lone pair on the central O would also mean the molecule was bent, thus making it polar. Therefore, Ozone is a polar molecule with a dipole moment of 0.53 D. The molecule can be represented as a resonance hybrid with two contributing structures, each with a single bond on one side and double bond on the other.

5) Phosphorus pentachloride, PCl₅

PCl₅ has a symmetrical geometry, the vector sum of the dipole moments of the different P-Cl bonds cancel each other. Therefore, the overall dipole moment of PCl₅ becomes 0.

Hope this helps!

6 0
3 years ago
3. A student measured 15.0 grams of ice in a beaker. The beaker was then
gregori [183]

Answer:

The heat that was used to melt the 15.0 grams of ice at 0°C is 4,950 Joules

Explanation:

The mass of ice in the beaker = 15.0 grams

The initial temperature of the ice = 0°C

The final temperature of the ice = 0°C

The latent heat of fusion of ice = 330 J/g

The heat required to melt a given mass of ice = The mass of the ice to be melted × The latent heat of fusion of ice

Therefore, the heat, Q, required to melt 15.0 g of ice = 15.0 g × 330 J/g = 4,950 J

The heat that was used to melt the 15.0 grams of ice = 4,950 Joules.

3 0
3 years ago
To demonstrate the formation of iron (iii) chloride from iron fillings
Pavel [41]

Iron (iii) chloride is obtained by vapor condensation from the reaction between chlorine gas and iron fillings.

<h3>How can iron (iii) chloride be formed from iron fillings?</h3>

Iron (ii) chloride can be formed from iron fillings in the laboratory as follows:

  • Iron fillings + Cl₂ → FeCl₃

Chlorine gas is introduced into a reaction vessel containing iron fillings and the iron (iii) chloride vapor formed is obtained by condensation.

In conclusion, iron (iii) chloride is formed by the the direct combination of iron fillings and chlorine gas.

Learn more about iron (iii) chloride at: brainly.com/question/14653649

#SPJ1

5 0
1 year ago
Set the Room temp. to -10.0 °C and observe. What is happening?
Lady bird [3.3K]

Answer:

its getting colder

Explanation:

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3 years ago
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maxonik [38]

Answer:

the direction of the object

Explanation:

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