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mash [69]
3 years ago
8

When a spaceship is traveling at 99% of the speed of light (Lorentz factor = 7), an astronomer on board the ship will find thata

. everything in the ship weighs seven times more. b. the ship has shrunk to one-seventh its original length. c. everyone on the ship talks seven times slower than normal. d. All of the above. e. None of the above. Everything seems normal to the astronaut on board.
Physics
1 answer:
Natali5045456 [20]3 years ago
6 0

Answer:

e) True. Measure the own values, so everything seems normal

Explanation:

In the case of special relativity, it is explicitly stated that the speed of light is constant and equal to c for all inertial observers. For this reason the measures of time and length are no longer the same for observers moving with respect to each other.

We call the time and the proper length the magnitude measured for an observer who does not move with respect to the measurement system.

In this case the astronomer is on the ship, for him he does not feel the movement of it, they are at rest with respect to each other. Therefore, their measurements are the so-called ones, this means that their values ​​do not change since the two go at the same speed.

In examining the final statements we have

A) False. The mass measures not

B) False. Measure own length

C) False

D) false

e) True. Measure the own values, so everything seems normal

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saul85 [17]
The mechanisms of reproductive isolation are:
1) Habitat isolation
2) Behavioral isolation
3) Mechanical isolation
4) Gametic isolation
The isolation happening here is behavioral isolation, because their different behavior patterns prevent the frogs from breeding.
4 0
2 years ago
If A > B, under what condition is |A-BI=|A|- IB|? a. Vectors A and B are in opposite directions b. Vectors A and B are in the
kupik [55]

Answer:

b) Vectors A and B are in the same direction.

Explanation:

To understand this problem we will say that vector A has a magnitude of 5 units and vector B a magnitude of 3 units. In the subtraction of vectors the initial parts of vectors always bind together. And the vector resulting from the subtraction is traced from the end of the second vector (B) to the end of the first vector (A).

The length of the resultant vector will be 5 - 3 = 2

In the attached image, we analyze case a), b), and d)

For a)

As we can see in the attached image the resultant vector has a length of 8 units.

For d)

As we can see in the attached image the resultant vector has a length of 5.83 units.

For b)

The resultant vector has a length of 2 units.

Therefore the case given in b) is true

5 0
3 years ago
A scientist notices that an oil slick floating on water when viewed from above has many different rainbow colors reflecting off
Semenov [28]

Answer:

Explanation:

In case of oil slick a thin layer of oil is formed on water . This thin layer creates a rainbow of colour . The phenomenon is due to interference of light waves , one reflected from the upper surface of oil and the other reflected from the lower surface of the oil.

For formation of bright colour

2 μ t = ( 2n + 1 ) λ / 2

μ is refractive index of oil ,  t is thickness of oil layer  λ is wave length of light falling on the layer .

given μ = 1.2 ,   λ = 750 x 10⁻⁹   ,

2 x 1.2 t = ( 2n + 1 ) 750 x 10⁻⁹ / 2

For minimum thickness n = 0

2.4 t = 375 x 10⁻⁹

t = 156.25 n m

B ) If the refractive index of layer of medium below oil is less than that of oil , the condition of formation of colour changes

The new condition is

2 μ t = n λ

2  x 1.5 t  = 750 nm ,         n = 1 for minimum wavelength .

t = 250 nm

C ) Light mostly transmitted means dark spot is formed at that point .

For that to be observed from water side , the condition is

2 μ t = ( 2n + 1 ) λ / 2

λ = 4μ t / ( 2n + 1 )

For maximum wavelength n = 0

λ = 4μ t

= 4 x 1.5 x 200 nm

= 1200 nm .

3 0
3 years ago
Which form of energy is due to the movement of electrons?
Kruka [31]
Electrical Energy : b
3 0
2 years ago
You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 294.0 kPa when the ther
Travka [436]

Answer: 361° C

Explanation:

Given

Initial pressure of the gas, P1 = 294 kPa

Final pressure of the gas, P2 = 500 kPa

Initial temperature of the gas, T1 = 100° C = 100 + 273 K = 373 K

Final temperature of the gas, T2 = ?

Let us assume that the gas is an ideal gas, then we use the equation below to solve

T2/T1 = P2/P1

T2 = T1 * (P2/P1)

T2 = (100 + 273) * (500 / 294)

T2 = 373 * (500 / 294)

T2 = 373 * 1.7

T2 = 634 K

T2 = 634 K - 273 K = 361° C

5 0
3 years ago
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