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3 years ago

Based on electronegativity differences, between which two elements will a bond result in a highly unequal sharing of electrons?

Chemistry

2 answers:

user100 [1]3 years ago

8 0

The type of bond that will result in unequal sharing of electrons will be C. Nitrogen and Oxygen.

frozen [14]3 years ago

3 0

Answer: The correct answer is Option D.

Explanation: Unequal sharing of electrons between the elements means that the bond is polar. This is very well studied with the help of electronegativity difference.

More the electronegative difference, more polar will be the bond and more will be unequal sharing of electrons and vice-versa.

Electronegativity values of the given elements:

1. Aluminium and Chlorine

Electronegativity of Aluminium = 1.61

Electronegativity of Chlorine = 3.16

Electronegative difference of Aluminium and chlorine = (3.16 - 1.61) = 1.55

2. Lead and sulfur

Electronegativity of Lead = 2.33

Electronegativity of Sulfur = 2.58

Electronegative difference of Lead and sulfur = (2.58 - 2.33) = 0.25

3. Nitrogen and oxygen

Electronegativity of Nitrogen = 3.04

Electronegativity of Oxygen = 3.44

Electronegative difference of Nitrogen and oxygen = (3.44 - 3.04) = 0.4

4. Lithium and Chlorine

Electronegativity of Lithium = 0.98

Electronegativity of Chlorine = 3.16

Electronegative difference of Lithium and chlorine = (3.16 - 0.98) = 2.18

As, the electronegativity difference of lithium and chlorine is the highest, so there will be the highest unequal sharing of electrons. This is an ionic compound.

Hence, the correct answer is option 4.

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N2+3H2 → 2NH3

s2008m [1.1K]

Explanation:

N2 (g) + H2 (g) gives out NH3 (g)

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.(If you balance the hydrogen reactant with a whole number first, I can guarantee you that you will have to give NH3 a new stoichiometric coefficient.)

N2 (g) + 3H2 (g) gives out 2NH3 (g)

The stoichiometric coefficients tell you that if we can somehow treat every component in the reaction as the same (like on a per-mol basis, hinthint), then one "[molar] equivalent" of nitrogen yields two [molar] equivalents of ammonia.

Luckily, one mol of anything is equal in quantity to one mol of anything else because the comparison is made in the units of mols.

So what do we do? Convert to

mols (remember the hint?).

28g N2 × 1 mol N2/ 2 × 14.007) g N2

= 0.9995 mol N2

At this point you don't even need to calculate the number of mols of H2 . Why? Because H2 is about 2 g/mol, which means we have over 10 mols of H2. We have 1 mol N2, and we need three times as many mols of H2 as we have

N2.

After doing the actual calculation you should realize that we have about 4 times as much H2 as we need. Therefore the limiting reagent is clearly N2.

Thus, we should yield 2×0.9995=1.9990 mols of NH3 (refer back to the reaction). So this is the second and last calculation we need to do:

1.9990 mol NH3 × 17.0307 g NH3/ 1 mol NH3

= 34.0444 g NH3

Hope it helpz~

4 0

2 years ago

Describe the day of June 21 at the North Pole in terms of daylight and darkness <br> ( science )

frosja888 [35]

On June 21, as seen from the North pole ...

-- the sun has been up, and it's been light outside,
for the past three months ... ever since March 21 .

-- The sun won't set, and it won't be dark outside,
for another three months ... until September 21.

-- Here at the North pole, it stays daylight for six months straight.
Today, on June 21, we're exactly halfway through the period of
continuous daylight.

7 0

3 years ago

How do you make a model of something you cannot see?

Vedmedyk [2.9K]

You have to imagine it

8 0

2 years ago

Read 2 more answers

Lewis structure for 2O2

Mrrafil [7]

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