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3 years ago

Why can’t kinetic emerger ever be greater than potential energy

2 answers:

5 0

Kinetic energy of an object can't be greater than potential energy. This is due to the reason that some of the energy is lost in the form of friction, heat energy, light energy etc. For example, a ball bounces to a height h in its first bounce.

melomori [17]3 years ago

4 0

Answer:

Kinetic energy of an object can't be greater than potential energy.

Explanation:

This is due to the reason that some of the energy is lost in the form of friction, heat energy, light energy etc. For example, a ball bounces to a height h in its first bounce.

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A banked circular highway curve is designed for traffic moving at 58 km/h. The radius of the curve is 201 m. Traffic is moving a

skelet666 [1.2K]

Answer:0.077

Explanation:

Given

banked designed for traffic moving at $58 km/h\approx 16.11 m/s$

Radius of the curve 201 m

Actual traffic velocity = $37 km/h approx 10.27 m/s$

For banking of road

$tan\theta =\frac{v^2}{rg}$

$tan\theta =\frac{16.11^2}{201\times 9.81}$

$\theta =7.49^{\circ}$

Centripetal acceleration is given by

$a=\frac{v^2}{r}$

Taking component of centripetal acceleration

along and perpendicular to surface

$a_{parallel}=\frac{v^2cos\theta }{r}$

$a_{perpendicular}=\frac{v^2sin\theta }{r}$

From FBD

$mgsin\theta -f_s=ma_{parallel}$

$f_s=mgsin\theta -ma_{parallel}$ ----1

where $f_s$ is frictional force

$N-mgcos\theta =ma_{perpedicular}$

$N=mgcos\theta +ma_{perpedicular}$ ----2

and we know coefficient of friction is given by

$\mu =\frac{f_s}{N}$

$\mu =\frac{mgsin\theta -ma_{parallel}}{mgcos\theta +ma_{perpedicular}}$

$\mu =\frac{gsin\theta -\frac{v^2cos\theta }{r}}{gcos\theta +\frac{v^2sin\theta }{r}}$

$\mu =\frac{1.2804-0.5202}{9.726+0.068}$

$\mu =0.077$

7 0

3 years ago

In what way could a random mutation provide an organism with<br> an advantage?

andreyandreev [35.5K]

Answer:

They are called beneficial mutations. They lead to new versions of proteins that help organisms adapt to changes in their environment. Beneficial mutations are essential for evolution to occur. They increase an organism's changes of surviving or reproducing, so they are likely to become more common over time.

Explanation:

7 0

3 years ago

6. A total of 135 J of work is done on a gaseous refrigerant as it undergoes compression. If

Gwar [14]

Answer:

Eh = 21 [J]

Removed as heat.

Explanation:

This is a case of energy conservation, we have to take into account the energies that go in and out of the system. In this case, 135 [J] of energy are entered in the form of work of the compressor to the chamber where the refrigerant is compressed, now of these 135 [J] 114 [J] were used as internal energy, this internal energy is used to increase the pressure and temperature of the refrigerant.

In this way the rest of the energy of the 135 [J] was lost in the form of heat to determine this loss of energy, we simply perform the arithmetic subtraction.

Eh = 135 - 114 = 21 [J]

Eh = 21 [J]

6 0

3 years ago

Did you think about this over Christmas? I did (-: Before Christmas a 65kg student consumes 2500 Cal each day and stays at the s

Gnesinka [82]

Answer:

a) Em = 332.8 J , b) # jump = 13, c) It is reasonable since there are not too many jumps , d) lower the calories consumed

Explanation:

a) Let's use energy conservation

Initial. On the floor

Em₀ = K = ½ m v²

Final. The highest point

Emf = U = m g h

Energy is conserved

Em₀ = Emf

½ m v² = m g h

h = ½ v² / g

h = ½ 3.2² /9.8

h = 0.52 m

b) When he was at home he maintained his weight with 2500 cal / day. In his parents' house he consumes 3500 cal / day, the excess of calories is

Q = 3500 -2500 = 1000cal / day

Let's reduce this value to the SI system

Q = 1000 cal (4,184 J / 1 cal) = 4186 J / day

Now the energy in each jump is

Em = K = ½ m v²

Em = ½ 65 3.2²

Em = 332.8 J

They indicate that the body can only use 25% of this energy

Em effec = 0.25 332.8 J

Em effec = 83.2 J

This is the energy that burns the body

Let's use a Proportion Rule (rule of three), if a jump spends 83.2J how much jump it needs to spend 1046 J

# jump = 1046 J (1 jump / 83.2 J)

# jump = 12.6 jumps / day

# jump = 13

c) It is reasonable since there are not too many jumps

d) That some days consume more vegetables to lower the calories consumed

7 0

4 years ago

g We saw in class that in a pendulum the string does no work. We also saw that the normal force does no work on an object slidin

Ymorist [56]

Answer:

From question (a) and (b) the pendulum motion is perpendicular to the force so the normal force will do no work and the tension in the string of the pendulum will not work

$i.e Normal \ Force(N) = mg cos \theta$

And $\theta = 90$ so

$N = 0$

An example will be a where a stone is attached to the end of a string and is made to move in a circular motion while keeping the other end of the string in a fixed position

A dog walking along a surface which has friction, here the frictional force would acting in the direction of the motion and this would do positive work

Explanation:

5 0

3 years ago

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