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chubhunter [2.5K]
3 years ago
14

It's a hot sunny day and you decide to go for a drive. When you open your car door, it's a lot hotter inside than outside. Why i

s that?
A).Air pollutants entering the car make the inside warmer.
B).A greenhouse effect—heat was let in through the windows and some was trapped inside.
C).Global warming—it's getting hotter everywhere you turn.
D).The hole in the ozone layer has caused higher temperatures.
Physics
2 answers:
vredina [299]3 years ago
8 0
The answer is B. Hope I helped!
Veronika [31]3 years ago
6 0

Answer:The correct answer is option B.

Explanation:

Green house effect: The process in which gases present in the atmosphere absorbs the heat of the Sun. Due to this trapped heat of Sun the temperature of Earth rises.

When we open the door of car on hot sunny day , the inside of a car is more hotter. This is because heat falling on the car's window pane gets trapped inside it and results in rise in temperature inside the car.

Hence, the correct answer is option B.

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If the man falls with his knees and ankles locked, the only cushion for his fall is a 0.480 cm give in the pads of his feet. Cal
Mariulka [41]

Answer:

The average force exerted on the man by the ground therefore is 153.319.53 N

Explanation:

Given the following information

Mass of man, m = 75 kg

height of fall, h = 0.48 cm

velocity just before landing,  v = 4.43 m/s

We therefore have

The work required to break the fall is equal to the kinetic energy of motion, just before touching the ground

Work done = Energy to absorb Kinetic Energy KE = 0.5·m·v²= F·h

Where:

F = Force required to break the fall

Therefore the force, F = (0.5·m·v² )/h

= 0.5×75 kg ×(4.43 m/s)²/(0.0048 m) = 153319.53 N

The average force exerted on him by the ground is therefore

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4 0
3 years ago
An electron emitted from a filament is travelling at 1.5 x 105 m/s when it enters an acceleration of an electron gun in a televi
Crank

Answer:

The acceleration of the electron is 1.457 x 10¹⁵ m/s².

Explanation:

Given;

initial velocity of the emitted electron, u = 1.5 x 10⁵ m/s

distance traveled by the electron, d = 0.01 m

final velocity of the electron, v = 5.4 x 10⁶ m/s

The acceleration of the electron is calculated as;

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(5.4 x 10⁶)² = (1.5 x 10⁵)² + (2 x 0.01)a

(2 x 0.01)a = (5.4 x 10⁶)² - (1.5 x 10⁵)²

(2 x 0.01)a = 2.91375 x 10¹³

a = \frac{2.91375 \ \times \ 10^{13}}{2 \ \times \ 0.01} \\\\a = 1.457 \ \times \ 10^{15} \ m/s^2

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