Answer:
160000000 kg.
Explanation:
p=mv
p=1.6x10^9
v=10m/s
rearrange and substitute:
(1.6x10^9)=m(10)
m=(1.6x10^9)/10
m= 1.6x10^8 kg.
Answer:
6 Newtons to the left.
Explanation:
We can convert this into a generic algebra equation by giving directions positive and negative values.
The 6 will be positive, and the 10 and 2 will be negative.
Add 10 and 2 to have 12.
6-12 = -6.
Therefore you have 6 newtons to the left (negative).
Answer:
-6327.45 Joules
650.375 Joules
378.47166 N
Explanation:
h = Height the bear slides from = 15 m
m = Mass of bear = 43 kg
g = Acceleration due to gravity = 9.81 m/s²
v = Velocity of bear = 5.5 m/s
f = Frictional force
Potential energy is given by

Change that occurs in the gravitational potential energy of the bear-Earth system during the slide is -6327.45 Joules
Kinetic energy is given by

Kinetic energy of the bear just before hitting the ground is 650.375 Joules
Change in total energy is given by

The frictional force that acts on the sliding bear is 378.47166 N
<span>Cells may appear inactive during this stage, but they are quite the opposite. This is the longest period of the complete cell cycle during which DNA replicates, the centrioles divide, and proteins are actively produced. </span>