1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
chubhunter [2.5K]
3 years ago
14

It's a hot sunny day and you decide to go for a drive. When you open your car door, it's a lot hotter inside than outside. Why i

s that?
A).Air pollutants entering the car make the inside warmer.
B).A greenhouse effect—heat was let in through the windows and some was trapped inside.
C).Global warming—it's getting hotter everywhere you turn.
D).The hole in the ozone layer has caused higher temperatures.
Physics
2 answers:
vredina [299]3 years ago
8 0
The answer is B. Hope I helped!
Veronika [31]3 years ago
6 0

Answer:The correct answer is option B.

Explanation:

Green house effect: The process in which gases present in the atmosphere absorbs the heat of the Sun. Due to this trapped heat of Sun the temperature of Earth rises.

When we open the door of car on hot sunny day , the inside of a car is more hotter. This is because heat falling on the car's window pane gets trapped inside it and results in rise in temperature inside the car.

Hence, the correct answer is option B.

You might be interested in
A car passes point “A” and then 120 meters later. It’s velocity was measured 21 m/s. If it’s acceleration was constant at 0.853
Norma-Jean [14]

Recall that

{v_f}^2-{v_i}^2=2a\Delta x

where v_i and v_f are the initial and final velocities, respecitvely; a is the acceleration; and \Delta x is the change in position.

So we have

\left(21\dfrac{\rm m}{\rm s}\right)^2-{v_i}^2=2\left(0.853\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m)

\implies v_i\approx\boxed{15.4\dfrac{\rm m}{\rm s}}

(Normally, this equation has two solutions, but we omit the negative one because the car is moving in one direction.)

7 0
3 years ago
Changing classes, you walk 20.0 m down a hall, turn left, and then walk 10.0 m down another hall. Define a coordinate system and
worty [1.4K]

Explanation:

Calculate position vectors in a multidimensional displacement problem. Solve for the displacement in two or three dimensions. Calculate the velocity vector 

7 0
3 years ago
Phương trình trạng thái tổng quát của khí lí tưởng diễn tả là​
tatyana61 [14]

Expla

pV/T=const goodluke

6 0
3 years ago
A static charge that is produced by a nearby objet is an?
Wittaler [7]
I believe that it is electric field
7 0
3 years ago
1) A boy drags a wooden crate with a mass of 20 kg, a distance of 12 m, across a rough level floor at a constant speed of 1.5 m/
mojhsa [17]

Answer: a) 49.560 and 21.13 b) i) 50 N, ii) 196 N iii) 196 N iv) 47.685 N

c) i) 594.72 ii) 0 iii) 0 iv) 0

d) 594.72

Explanation: question a)

The force is inclined at an angle of 25° to the horizontal

The horizontal component of force = 50 cos 25° = 49.560 N

The vertical component of force = 50 sin 30°= 21.130N

Question b)

i) according to the question applied force is 50 N

ii) if g = 9.8m/s², w=mg where m = mass of object = 20kg hence weight = 20* 9.8 = 196 N

iii) the normal force is the force the floor exerts on the body as a result of the weight of the object.

Normal reaction R = W = mg, we already deduced that w = mg, hence R = 196 N.

iv) according to newton's laws of motion

F - Fr = ma

F = applied force = horizontal component of force = 49.560 N.

We need to get the acceleration (a) by using Newton laws of motion before we can be able to compute the frictional force..

The body started from rest hence initial velocity u = 0

Final velocity v = 1.5m/s distance covered (s) = 12m

v ² = u² + 2as

But u = 0

v² = 2as

1.5² = 2(a) * 12

2.25 = 24a

a = 2.25/24 = 0.09735m/s²

From F - Fr = ma

49.560 - Fr = 20 * 0.09735

49.560 - Fr = 1.875

Fr = 49.560 - 1.875

Fr = 47.685 N

Question c)

i) The applied force = 49.560 N, distance covered = 12m

Work done = force * distance

Work done = 49.560 * 12

Work done = 594.72 J

ii) the weight of the object does not make the object move a distance, hence work done = 0 ( since distance covered is 0)

iii) the normal force is the same thing as the weight and they did not cover any distance hence work done is zero.

iv) the frictional force does not cover any distance, hence work done is zero.

Question d)

The total work done = work done by applied force + work done by weight + work done by normal reaction + work done by frictional force.

Total work done = 594.72 + 0 + 0 + 0 = 594.72 J

8 0
3 years ago
Other questions:
  • According to the periodic table, which of the following is the correct symbol for
    15·1 answer
  • What is the amount of heat, in calories, given off from a 5 g piece of aluminum when it cools from 80°C to 20°C? The specific he
    15·1 answer
  • The process that uses a half-life in its computation is
    6·1 answer
  • On a safari, a team of naturalists sets out toward a research station located 4.63 km away in a direction 38.7 ° north of east.
    13·2 answers
  • A parallel plate capacitor is attached to a battery to create a potential difference of 12V The battery is then disconnected and
    7·1 answer
  • What is the name given to the semiconductor device that has three or more elements?
    5·1 answer
  • How do we calculate the "average" of the measurements?
    12·1 answer
  • Mars is 1.52 times as far from the Sun as Earth is. Predict the time required for Mars to orbit the Sun in Earth days.
    15·1 answer
  • 17
    13·1 answer
  • Two point charges attract each other with an electric force of magnitude F. If the charge on one of the particles is reduced to
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!