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IRINA_888 [86]
3 years ago
11

If the patient has to be administered a dosage of 2 tablets every 8 hours for 7 days, what is the number of tablets required for

the prescribed dosage?
Chemistry
1 answer:
Lilit [14]3 years ago
6 0
If the patient has to take 2 tablets every 8 hours for 7 days.
 24/8=3     3*2=6
this means that he patient will have to take 6 tablets every day. 
6*7=42   And the patient must take 42 tablets in all 7 days
Hope this helps! :)
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An analytical chemist weighs out 0.055g of an unknown triprotic acid into a 250mL volumetric flask and dilutes to the mark with
Katarina [22]

Answer:

Mass of the unknown acid is 4.0g

Explanation:

The determine the molar mass of the unknown acid, the steps below can be followed

Firstly, determine the concentration of the acid, the formula below can be used;

ConcA × Va/ConcB × Vb = Na/Nb

Where ConcA is the concentration of the unknown acid

ConcB is the concentration of the NaOH base

Va is the volume of acid and Vb is the volume of base

Since, the titration was said to have reached an equivalent point, it means the number of moles of the acid (Na) was equal to the number of moles of the base (Nb) and thus both will be assumed to be 1

Thus

ConcA × 250/0.13 × 6.6 = 1/1

ConcA = 0.13 × 6.6/250

ConcA = 0.003432M

Then, determine the actual number of moles (n) of the unknown acid used,

ConcA = no of moles of acid/volume of acid (in dm³ or L)

To convert mL to L, we divide by 1000

Hence, 250ml = 0.25L

0.003432 = n/0.25

n = 0.003432 × 0.25

n = 0.01373 moles

To determine the molar mass;

n = mass/molar mass

The mass was given in the question to be 0.055g

Thus

0.01373 = 0.055/molar mass

molar mass = 0.055/0.01373

molar mass = 4.0g

5 0
3 years ago
2. How many orbitals are in the following sublevels?
Lostsunrise [7]

Explanation:

The number of orbitals in the sublevels are given below:

     Sublevels                   Orbitals

        s                                  1

        p                                 3

        d                                 5

        f                                   7

a. ls       -  1 orbital

b. 5s      - 1 orbital

c. 4d     - 5 orbitals

d. 4f       - 7 orbitals

e. 7s       - 1 orbital

f. 3p       - 3 orbitals

g. Entire 5th principal energy level : for s, p ,  f  

          1 + 3 + 5 + 7 + 9  = 25

h. 6d   - 5

8 0
3 years ago
WILL GIVE BRAINLEST! --
Paladinen [302]

Answer:

d

Explanation:

5 0
3 years ago
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Write a statement that shows how the charge of an ion relates to the number of electrons transferred.
DanielleElmas [232]

Answer:

Q = ne

Explanation:

Ler n be the number of electrons transferred and Q be the charge of an ion.

The net charge on the object is then given by :

Q = ne

Where

e is the electronic charge

Hence, the charge of an ion relates to the number of electrons transferred is equal to Q = ne.

7 0
3 years ago
Estimate the molar mass of a gas that effuses at 1.80 times the effusion rate of carbon dioxide. answer in units of g/mol.
Effectus [21]
From Grahams Law the rates of effusion of two gases are inversely proportional to the square roots of their molar masses at the same temperature and pressure.
Therefore; R1/R2 = √mm2/√mm1
The molecular mass of Carbon dioxide is 44 g
Hence;  1.8 = √(44/x
             3.24 = 44/x
                x = 44/3.24
                   = 13.58 
Therefore, the molar mass of the other gas is 13.58 g/mol
           
3 0
3 years ago
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