Two balls are thrown against a wall with the same velocity. The first ball is made of rubber and bounces straight back with some
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The force required to extend a rod increases as the cross sectional area
increases.
The rod that experiences the largest force is <u>rod B</u>
Reason:
The elongation of a rod by the application of a force is given by the
following formula;
From the above equation, we have that the elongation is inversely
proportional to the cross sectional area, such that the extension of a rod by
a given force reduces as the cross sectional area of the rod increases.
Therefore, the force required to extend the length of a rod by a specific
amount increases as the cross sectional area of the rod increases,
indicating that the rod with the largest cross sectional area require the
most force and therefore, experiences the largest force.
The rod that experiences the largest force is the rod with the largest cross
sectional area, which is <u>rod B</u>
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Answer:
Explanation:
Hello!
In this case, for this melting process, we can identify two sub-processes in order to take the stainless steel from solid to liquid:
1. Heat up from 298.15 K to 1673 K.
2. Undergo the phase transition.
Both process have an associated enthalpy as shown below:
Therefore, the required heat is:
Notice the problem is not providing neither the mass or volume, that is why we assumed the mass is 1 g; however, it can be changed to the mass you are given.
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Answer:
E1 = 10.15 * 10^4 N/C
E2 = 0
E3 = 10.15 *10^4 N/C
Explanation:
Given data:
Two 13 cm-long thin glass rods ( L ) = 0.13 m
charge (Q) = +11nC
distance between thin glass rods = 4 cm .
<u>Calculate the electric field strengths </u>
electric charge due to a single glass rod in the question ( E ) =
equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced
applying equation 1 to determine E1
E1 =
( distance from 1 rod is 0.01 m and from the other rod is 0.03 )
=
= 10.15 * 10^4 N/C
applying equation 1 to determine E2
E2 =
therefore E2 = 0
E1 = E3
hence E3 = 10.15*10^4 N/C