All categories

2 years ago

How much force was applied to an object if was moved 2 meters and the work done on the object was 8 joules?

Physics

2 answers:

serious [3.7K]2 years ago

6 0

Answer:

The answer is 4N or B

Explanation:

Just the equation W = F x D.

We have W = 8 J and D = 2 m using algebra ....

8J/2m = F ... F = 4.

Natasha2012 [34]2 years ago

6 0

Answer:

B 4N

Explanation:

You might be interested in

Volume can be measured in: A. cubic centimeters. B. centimeters. C. square centimeters.

Ad libitum [116K]

Answer-

A. cubic centimeters.

Hope this helps!

8 0

2 years ago

Read 2 more answers

A non-_____ rock has interlocking grains with no specific pattern.

Kazeer [188]

A non foliated rock has interlocking grains with no specific pattern.

3 0

3 years ago

Read 2 more answers

Ask Your Teacher Cam Newton of the Carolina Panthers throws a perfect football spiral at 6.9 rev/s. The radius of a pro football

faltersainse [42]

Answer:

$a=159.32\ m/s^2$

Explanation:

It is given that,

Angular speed of the football spiral, $\omega=6.9\ rev/s=43.35\ rad/s$

Radius of a pro football, r = 8.5 cm = 0.085 m

The velocity is given by :

$v=r\omega$

$v=0.085\times 43.35$

v = 3.68 m/s

The centripetal acceleration is given by :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(3.68)^2}{0.085}$

$a=159.32\ m/s^2$

So, the centripetal acceleration of the laces on the football is $159.32\ m/s^2$ . Hence, this is the required solution.

6 0

3 years ago

An airplane dropped a flare from a height of 2860 feet above a lake. How many seconds did it take for the flare to reach the wat

KATRIN_1 [288]

Answer: 13.2 seconds.

Explanation: using equation of motion; S= ut +1/2at² where u = initial velocity=0

S= distance travelled

a = acceleration due gravity

t= time.

1 foot = 0.305m so,

S= 2860 feet =872.3m

S= ut+1/2 at²

872.3 = 0×t + 1/2×10 × t²

872.3 =0 + 5t²

T²= 872.3/5

T²= 174.46

Take the square root of T we then have;

t = 13.2 seconds to one decimal place.

8 0

2 years ago

Read 2 more answers

An object is placed to the left of a convex mirror, such that the object-to-image distance is 140 cm.

labwork [276]

Answer:

The focal length of the mirror is 52.5 cm.

Explanation:

Given that,

Object to Image distance d = 140 cm

Image distance v= 35 cm

We need to calculate the object distance

$u = d-v$

$u = 140-35=105\ cm$

We need to calculate the focal length

Using formula of mirror

$\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}$

Put the value into the formula

$\dfrac{1}{f}=\dfrac{1}{-105}+\dfrac{1}{35}$

$\dfrac{1}{f}=\dfrac{2}{105}$

$f=52.5\ cm$

Hence, The focal length of the mirror is 52.5 cm.

6 0

3 years ago