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Nikolay [14]
3 years ago
15

Which of the following is true for the equilibrium constant of a reaction? It is a ratio of the concentrations in a reaction. It

remains the same at different temperatures. It is represented by the symbol H. Its value is always close to 1.
Chemistry
1 answer:
Luda [366]3 years ago
5 0

Answer:

It is a ratio of the concentrations in a reaction.

Explanation:

  • For an equilibrium reaction:

<em>reactants ⇄ products</em>

K (equilibrium constant) = [products]/[reactants].

  • <em>The equilibrium constant is a ratio of the concentration of products to reactants.</em>

<em></em>

  • So, the right choice is:

<em>It is a ratio of the concentrations in a reaction. </em>

<em></em>

You might be interested in
Which electron configuration represents the
Pachacha [2.7K]

This problem is asking for the electron configuration of an excited atom of gallium, which according to the group it is, its excited state will theoretically be Ga³⁺, since it is a metal and loses three or less electrons, that is why it turns out positive. After writing the electron configuration, we realize the answer must be 2-8-17-4 according to the following:

<h3>Electron configurations:</h3><h3 />

In chemistry, electron configurations allow us arrange the electrons of an element according to specific energy levels and orbitals. In such a case, it turns out possible to write Gallium's electron configuration in its ground-state as follows:

1s^22s^22p^63s^23p^64s^23d^{10}4p^1

However, since the given choices do not match with a charge of 3+ as formerly explained, we assume this gallium atom will be excited to 1+, due to the fact that the third energy level comprising 18 electrons, will give one to the fourth energy level, turning out in an electron configuration of:

1s^22s^22p^63s^23p^64s^23d^{9}4p^2

Which matches with 2-8-17-4 as two electrons are present in the first energy level, eight in the second one, now seventeen in the third one and four in the fourth one.

Learn more about electron configurations: brainly.com/question/5524513

5 0
3 years ago
What is the E°cell for the cell represented by the combination of the following half-reactions? ClO4–(aq) + 8H+(aq) + 8e– Cl–(aq
Vinvika [58]

Answer:

The E°cell for the cell represented by the combination of the given half-reactions is 0.398 V

Explanation:

Oxide-reduction reactions, also called redox, involve the transfer or transfer of electrons between two or more chemical species. In these reactions two substances interact: the reducing agent and the oxidizing agent.

The gain of electrons is called reduction and the loss of electrons oxidation. That is to say, there is oxidation whenever an atom or group of atoms loses electrons (or increases its positive charges) and in the reduction an atom or group of atoms gains electrons, increasing its negative charges or decreasing the positive ones.

The species that supplies electrons is the reducing agent (that is, it is that species that oxidizes, yielding electrons and increasing its positive charge, or decreasing the negative one causing the reduction of the other species) and the one that gains them is the oxidizing agent ( that is, it is that species that is reduced, capturing electrons and increasing its negative charge, or decreasing its positive charge, causing oxidation of the other species).

This is the type of reaction that occurs in this case.

ClO₄⁻(aq) + 8 H⁺ (aq) + 8 e⁻ ⇔ Cl⁻ (aq) + 4 H₂O(l) E° = 1.389 V

VO₂⁺(aq) + 2 H⁺(aq) + e⁻ ⇔ VO⁺(aq) + H₂O(l) E° = 0.991 V

In this case both are written as reductions, and their E ° values ​​as well. The species that has the greatest potential for reduction will be the species that will be reduced, that is, it will be the oxidizing agent. In this case, it will be the first half-reaction expressed.  Therefore, to obtain a reaction, the second semi-reaction must be reversed to be an oxidation, maintaining its constant value. Then:

Reduction: ClO₄⁻(aq) + 8 H⁺ (aq) + 8 e⁻ ⇔ Cl⁻ (aq) + 4 H₂O(l) E° = 1.389 V

Oxidation: VO⁺(aq) + H₂O(l) ⇔ VO₂⁺(aq) + 2 H⁺(aq) + e⁻ E° = 0.991 V

<em>E°cell=Ereduction - Eoxidation</em>

E°cell=1.389 V - 0.991 V

<em>E°cell=0.398 V</em>

Then <u><em>the E°cell for the cell represented by the combination of the given half-reactions is 0.398 V.</em></u>

Another way of thinking is that, by inverting the second semi-reaction to be an oxidation, the value of E ° is reversed in the sign, unlike the previous case in which it was constant. Then:

Reduction: ClO₄⁻(aq) + 8 H⁺ (aq) + 8 e⁻ ⇔ Cl⁻ (aq) + 4 H₂O(l) E° = 1.389 V

Oxidation: VO⁺(aq) + H₂O(l) ⇔ VO₂⁺(aq) + 2 H⁺(aq) + e⁻ E° = -0.991 V

In this case:

E°cell=Ereduction + Eoxidation=

E°cell=1.389 V + (-0.991 V)=1.389 V-0.991 V

<em>E°cell=0.398 V</em>

Note that the result obtained is the same. This indicates that either of the two ways proposed is correct, and you will use the one that is most comfortable for you.

4 0
3 years ago
The _______ of an atom are negatively charged. a. protons b. negatrons c. neutrons d. electrons
PIT_PIT [208]
Protons = +1
negatrons = -1
neutrons = 0
<span>electrons = -1
</span>
<span>negatrons are like positrons and they are subatomic particles and are not present in atoms 
</span>
so electrons are negatively charged and are present in atoms 

hope that helps
7 0
3 years ago
Read 2 more answers
Methanogens are able to live in an ________ environment. extremely acidic. extremely salty. extremely hot or anaerobic.
vredina [299]
Anaerobic ............................................
6 0
3 years ago
How many jelly belly beans to get 50g of glucose?
Hunter-Best [27]
I believe its 28 jelly beans=50g glucose
7 0
3 years ago
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