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3 years ago

Which formula is an empirical formula?

Chemistry

2 answers:

Naily [24]3 years ago

6 0

CH4 as empirical formula is the simplest ratio of all the atoms in a molecule

Irina18 [472]3 years ago

5 0

Answer: The empirical formula is $CH_{4}$

Explanation:

Empirical formula is defined as the formula in which atoms in a compound are present in simplest whole number ratios.

For the given options:

Option A: $C_4H_{10}$

As, the atoms are not in the smallest whole number ratio, it is not the empirical formula. The empirical formula of this will be $C_2H_5$

Option B: $C_3H_{6}$

As, the atoms are not in the smallest whole number ratio, it is not the empirical formula. The empirical formula of this will be $CH_2$

Option C: $CH_{4}$

As, the atoms are in the smallest whole number ratio, it is the empirical formula.

Option D: $C_2H_{6}$

As, the atoms are not in the smallest whole number ratio, it is not the empirical formula. The empirical formula of this will be $CH_3$

Hence, the empirical formula is $CH_{4}$

You might be interested in

Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

3 years ago

what is a major drawback of using fossil fuels they warmn the planet they contain no greenohuse gases

Charra [1.4K]

The major drawback of fossil fuels is that they warm the planet i.e. they cause global warming.

The reaction typically gives off heat and light as well. The general equation for a complete combustion reaction is:

Fuel + O2 → CO2 + H2O + ENERGY

<h3>Disadvantages of Fossil fuels</h3>

The term "fossil fuels" refers to flammable organic geologic formations, including dead organic matter that has been buried hundreds of feet beneath sediment.

Fossil fuel emissions include various oxides, such as carbon, nitrogen, and sulfate, which cause acid rain and harm the soil's fertility and water quality.
Both coal and petroleum burning discharge a significant amount of pollutants into the atmosphere, contributing to pollution levels.
Gases like carbon dioxide are released through the burning of fossil fuels, which aids in climate change.