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Allisa [31]
4 years ago
11

Yellow cake is a uranium ore that contains about 75% U3O8 (842 g/mol), and can be further refined to extract pure uranium. How m

any grams of yellow cake must be processed to produce 3.5 kg of pure uranium?
1) 2.6 kg.
2) 3.0 kg.
3) 4.1 kg.
4) 4.7 kg.
5) 5.5 kg.
Chemistry
1 answer:
alex41 [277]4 years ago
6 0

Answer : The correct option is, (5) 5.5 kg

Explanation :

As we are given that yellow cake is a uranium ore that contains about 75 % U_3O_8. That means,

Mass of U_3O_8 = 75 g

Mass of yellow cake = 100 g

Molar mass of uranium = 238 g/mol

Molar mass of U_3O_8 = 842 g/mol

First we have to calculate the mass of pure uranium.

As, 842 g of U_3O_8 contains 3\times 238g of pure uranium

So, 75 g of U_3O_8 contains \frac{75}{842}\times 3\times 238g=63.59g of pure uranium

Now we have to calculate the mass of yellow cake.

As, 63.59 g of pure uranium present in 100 g of yellow cake

So, 3.5 kg of pure uranium present in \frac{100g}{63.59g}\times 3.5kg=5.5kg of yellow cake

Thus, the mass of yellow cake processed to produce 3.5 kg of pure uranium must be, 5.5 kg

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VMariaS [17]

Answer:

3Mg + Fe₂O₃ → 3MgO + 2Fe.

Explanation:

  • To balance the equation, you should apply the law of conservation of mass for the equations.
  • The law of conservation of mass states that the no. of each atom is equal in both sides (reactants and products).
  • The balanced equation is:

<em>3Mg + Fe₂O₃ → 3MgO + 2Fe.</em>

<em></em>

That 3.0 mole of Mg react with 1.0 mole of Fe₂O₃ to produce 3.0 moles of MgO and 2.0 moles of Fe.

  • The no. of all atoms is the same in both of reactants and products side.

Mg (3), Fe (2), and O (3).

8 0
3 years ago
A square chunk of plastic has a length of 5 cm, width of 5 cm and height of 5 cm. It has a mass of 200 g. What is it’s density
vichka [17]

Answer:

1.6g/mL

Explanation:

Density equation is D=m/v

Density = g/mL

m=mass of sample in grams

v = volume of sample in mL

The volume of a square can be calculated by V=l*w*h.

In this case it is 5cm*5cm*5cm = 125cm^3

Since we know that 1cm^3 ~ 1mL we can convert the volume to mL as so:

125cm^3 (1mL/(1cm^3)) = 125mL

Then simply plug into the density equation:

D=200g/125mL = 1.6g/mL

3 0
3 years ago
A 7.74 L balloon is filled with water at 3.88 atm. If the balloon is squeezed into a 0.23 L beaker and does NOT burst, what is t
Vladimir [108]

Answer:

131 atm

Explanation:

To find the new pressure, you need to use Boyle's Law:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.

P₁ = 3.88 atm                       P₂ = ? atm

V₁ = 7.74 L                           V₂ = 0.23 L

P₁V₁ = P₂V₂                                                      <----- Boyle's Law

(3.88 atm)(7.74 L) = P₂(0.23 L)                       <----- Insert values

30.0312 = P₂(0.23 L)                                      <----- Simplify left side

131 = P₂                                                          <----- Divide both sides by 0.23

6 0
2 years ago
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choli [55]

Answer:

They have electrons in their 3d- and 4s-orbital for bond formation.

Explanation:

d- metals or transition metal are metal which form ion with partially filled d-orbital. Examples are iron and manganese.

The metals have 2 electrons in their 4s orbital. If only this is used for bonding, they will form compounds where they have oxidation State of +2 as seen in MnO.

If two 4s and one of 3d electrons are used, oxidation state of +3 is formed as seen in FeCl3.

If two 2s electron I used with two 3d electrons, compound with oxidation state of +4 is formed as seen in MnO2

4 0
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answer: -230kJ
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