Answer:107.1 g, 124.1 g
Explanation:
The equation of the reaction is;
Al2S3(s) + 6H20(l) ----> 2Al(OH)3(s) + 3H2S(g)
Hence;
For Al2S3
Number of moles= reacting mass/molar mass
Number of moles = 158g/150gmol-1 =1.05 moles
If 1 mole of Al2S3 yields 3 moles of H2S
1.05 moles of Al2S will yield
1.05 × 3/1 = 3.15 moles
Mass of H2S = 3.15moles × 34 gmol-1 = 107.1 g
For water
Number of moles of water = 131g/18gmol-1= 7.3 moles
6 moles of water yields 3 moles of H2S
7.3 moles of water will yield 7.3 × 3/6 = 3.65 moles of H2S
3.65 moles × 34 gmol-1 =124.1 g
Mg is magnesium. NO3 is nitrate. This gives you magnesium nitrate as an answer.
Answer is: 6,16 kJ.
1) changing temperature of ice from -25°C to 0°C.
Q₁ = m·C·ΔT
Q₁ = 18 g · 2 J/g·°C · 25°C
Q₁ = 900 J.
m(H₂O) = 1mol · 18 g/mol = 18 g.
C - <span>specific heat of ice.
</span>2) changing temperature of water from 0°C to 70°C.
Q₁ = m·C·ΔT
Q₁ = 18 g · 4,18 J/g·°C · 70°C
Q₁ = 5266,8 J.
C - specific heat of water.
Q = Q₁ + Q₂ = 900 J + 5266,8 J
Q = 6166,8 J = 6,16 kJ.
Answer:
The mass of material is 96.12 g
.
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Symbol:
The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.
Given data:
density of material = 2.7 g/mL
volume= 35.6 mL
mass= ? (in g)
Now we will put the values in the formula,
d= m/v
m=d×v
m= 2.7 g/mL × 35.6 mL
m= 96.12 g
so, the mass of material is 96.12 g
.
Answer:
A balanced chemical equation explicitly provides you with the
a. conditions under which the reaction occurs.
b. molar masses of the reactants and products.
c. conversion factors needed to solve a stoichiometry problem.
d. mole ratios needed to solve a stoichiometry problem.
The correct answer to the question is
d. mole ratios needed to solve a stoichiometry problem.
Explanation:
A chemical reaction is sad to be balanced if it contains the complete list of reactants and products present in their relative proportions. The amounts of reactants and products can be calculated from a balanced chemical reaction equation by applying a process known as stoichiometry
An example of stoichiometry is the formation of two moles of water from one mole of oxygen and two moles of hydrogen
