The stone reaches the wall at a height of <u>1.62 m</u>.
The stone lands at a point <u>24.5 m</u> from the point of projection.
The stone is projected horizontally with a velocity u at a height <em>h</em> from the ground. The wall is located at a distance <em>x</em> from the point of projection. The stone takes a time <em>t</em> to reach the wall and in the same time the stone falls a vertical distance <em>y</em>.
The horizontal distance <em>x</em> is traveled with a constant velocity <em>u</em>.
Calculate the time taken <em>t</em>.
The stone's initial vertical velocity is zero. It falls through a distance <em>y</em> in the time <em>t</em> under the action of acceleration due to gravity <em>g</em>.
The height <em>h₁ </em>of the stone above the ground when it reaches the wall is given by,
When the stone reaches the wall, its height from the ground is <u>1.62m.</u>
The stone thus crosses over the wall, since the height of the wall is 1 m. It reaches the ground at a distance <em>R</em> from the point of projection. If the time taken by the stone to reach the ground is <em>t₁, </em>then,
Calculate the time taken by the stone to reach the ground.
The horizontal distance traveled by the stone is given by,
The stone lands at point 24.5 m from the point of projection and 10.5 m from the wall.