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True [87]
3 years ago
6

4 of 5 Constants There are two categories of ultraviolet light. Ultraviolet A (UVA) has a wavelength ranging from 320 nm to 400

nm. It is necessary for the production of vitamin D. UVB, with a wavelength in vacuum between 280 nm and 320 nm, is more dangerous because it is much more likely to cause skin cancer. Find the frequency ranges of UVA.
Physics
2 answers:
pantera1 [17]3 years ago
8 0

Answer: UVA rays occupy the frequency range between 7.1 . 10¹⁴ and 9.4. 10¹⁴ Hz.

Explanation:

UV rays are simply electromagnetic waves, which wavelength is just below the visible spectrum (hance the name ultraviolet, meaning beyond violet).

As any elecromagnetic wave, propagates in the free space at the same speed that light does, i.e. 3.10⁸ m/s.

Also, we know that there exists a direct relationship between the wave speed, her wavelength (distance travelled by the wave during one cycle time) and the frequency (the inverse of the time needed to complete one cycle).

This relationship can be written as the following equation:

v = λ . f   ⇒  f = v/λ

Replacing by the extreme wavelengths, we find the corrresponding limit frequencies as follows:

f₁ = 3.10⁸ m/s / 320 . 10⁻⁹ m  ⇒ f₁ = 9.4 . 10¹⁴ Hz.

f₂ = 3.10⁸ m/s / 400 . 10⁻⁹ m ⇒ f₂ = 7.1 . 10¹⁴ Hz.

ziro4ka [17]3 years ago
7 0

Answer:

<u><em>The answer is</em></u>: <u>The wavelength is approximately between 10 nm (10 x 10-9 m) and 400 nm (400 x 10-9 m).</u>

Explanation:

Ultraviolet radiation or UV radiation is called electromagnetic radiation whose wavelength is approximately between 10 nm (10 x 10-9 m) and 400 nm (400 x 10-9 m). Its name comes from the fact that its range starts from shorter wavelengths than what we humans identify as the violet color, but that light or wavelength is invisible to the human eye by being above the visible spectrum.

Name -  Abbreviation - Wavelength (nm) - Energy per photon (eV)

Ultraviolet A (long wave) -UVA- 400 - 315          3.10 - 3.94

Ultraviolet B (medium) -UVB-     315 - 280          3.94 - 4.43

UV C (shortwave) -UVC-            280 - 100           4.43 - 12.40

Near ultraviolet (near) -NUV-    400 - 300           3.10 - 4.13

Middle ultraviolet (middle) -MUV- 300 - 200      4.13 - 6.20

Far ultraviolet (far) -FUV-           200 - 122            6.20 - 10.16

Lyman-alpha -H line Lyman-α / Ly-α- 122 - 121    10,16 - 10,25

Vacuum ultraviolet -VUV-          200 - 10              6.20 - 124

UV ultraviolet -EU-                      121 - 10               10.25 - 124

The types of UV radiation (A B and C) are related to the damage they cause in humans: UV-C radiation is the most harmful to life.

<u><em>The answer is</em></u>: <u>The wavelength is approximately between 10 nm (10 x 10-9 m) and 400 nm (400 x 10-9 m).</u>

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pshichka [43]

Answer:

a)  P = 807.85 N,  b)  P = 392.15 N,  c)  P = 444.12 N

Explanation:

For this exercise, let's use Newton's second law, let's set a reference frame with the x-axis parallel to the plane and the direction rising as positive, and the y-axis perpendicular to the plane.

Let's use trigonometry to break down the weight

         sin θ = Wₓ / W

         cos θ = W_y / W

         Wₓ = W sin θ

         W_y = W cos θ

         Wₓ = 1200 sin 30 = 600 N

          W_y = 1200 cos 30 = 1039.23 N

Y axis  

      N- W_y = 0

      N = W_y = 1039.23 N

Remember that the friction force always opposes the movement

a) in this case, the system will begin to move upwards, which is why friction is static

       P -Wₓ -fr = 0

       P = Wₓ + fr

as the system is moving the friction coefficient is dynamic

      fr = μ N

      fr = 0.20 1039.23

      fr = 207.85 N

we substitute

       P = 600+ 207.85

       P = 807.85 N

b) to avoid downward movement implies that the system is stopped, therefore the friction coefficient is static

        P + fr -Wx = 0

       fr = μ N

       fr = 0.20 1039.23

        fr = 207.85 N

we substitute

        P =  Wₓ -fr

        P = 600 - 207,846

        P = 392.15 N

c) as the movement is continuous, the friction coefficient is dynamic

         P - Wₓ + fr = 0

         P = Wₓ - fr

         fr = 0.15 1039.23

         fr = 155.88 N

         P = 600 - 155.88

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Even if this happened at the same time in every orbit, the date would change, because there are not 27.32 days in a month.

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She's in the air for 1.1 second before she hits the water.

Moving horizontally at 1.92 m/s for 1.1 second, she sails out away from the platform

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A motorcycle, which has an initial linear speed of 9.7 m/s, decelerates to a speed of 4.0 m/s in 4.4 s. Each wheel has a radius
Morgarella [4.7K]

Hi there!

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We can use the following equation:

vf = vi + at

Plug in given values:

4 = 9.7 + 4.4a

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a = -1.295 m/s²

We can use the following equation to convert from linear to angular acceleration:

a = αr

a/r = α

Thus:

-1.295/0.61 = -2.124 rad/sec² ⇒ 2.124 rad/sec² since counterclockwise is positive.

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θ = ωit + 1/2αt²

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v = ωr

v/r = ω

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Plug into the equation:

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3 years ago
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stepan [7]
We can calculate the acceleration of Cole due to friction using Newton's second law of motion:
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a= \frac{F}{m}= \frac{-50 N}{100 kg}=-0.5 m/s^2

Now we can use the following formula to calculate the distance covered by Cole and the sled before stopping:
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where
v_f=0 is the final speed of the sled
v_i=5 m/s is the initial speed
d is the distance covered

By rearranging the equation, we find d:
d= \frac{v_f^2-v_i^2}{2a}= \frac{-(5 m/s)^2}{2 \cdot (-0.5 m/s^2)}=25 m
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