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True [87]
4 years ago
6

4 of 5 Constants There are two categories of ultraviolet light. Ultraviolet A (UVA) has a wavelength ranging from 320 nm to 400

nm. It is necessary for the production of vitamin D. UVB, with a wavelength in vacuum between 280 nm and 320 nm, is more dangerous because it is much more likely to cause skin cancer. Find the frequency ranges of UVA.
Physics
2 answers:
pantera1 [17]4 years ago
8 0

Answer: UVA rays occupy the frequency range between 7.1 . 10¹⁴ and 9.4. 10¹⁴ Hz.

Explanation:

UV rays are simply electromagnetic waves, which wavelength is just below the visible spectrum (hance the name ultraviolet, meaning beyond violet).

As any elecromagnetic wave, propagates in the free space at the same speed that light does, i.e. 3.10⁸ m/s.

Also, we know that there exists a direct relationship between the wave speed, her wavelength (distance travelled by the wave during one cycle time) and the frequency (the inverse of the time needed to complete one cycle).

This relationship can be written as the following equation:

v = λ . f   ⇒  f = v/λ

Replacing by the extreme wavelengths, we find the corrresponding limit frequencies as follows:

f₁ = 3.10⁸ m/s / 320 . 10⁻⁹ m  ⇒ f₁ = 9.4 . 10¹⁴ Hz.

f₂ = 3.10⁸ m/s / 400 . 10⁻⁹ m ⇒ f₂ = 7.1 . 10¹⁴ Hz.

ziro4ka [17]4 years ago
7 0

Answer:

<u><em>The answer is</em></u>: <u>The wavelength is approximately between 10 nm (10 x 10-9 m) and 400 nm (400 x 10-9 m).</u>

Explanation:

Ultraviolet radiation or UV radiation is called electromagnetic radiation whose wavelength is approximately between 10 nm (10 x 10-9 m) and 400 nm (400 x 10-9 m). Its name comes from the fact that its range starts from shorter wavelengths than what we humans identify as the violet color, but that light or wavelength is invisible to the human eye by being above the visible spectrum.

Name -  Abbreviation - Wavelength (nm) - Energy per photon (eV)

Ultraviolet A (long wave) -UVA- 400 - 315          3.10 - 3.94

Ultraviolet B (medium) -UVB-     315 - 280          3.94 - 4.43

UV C (shortwave) -UVC-            280 - 100           4.43 - 12.40

Near ultraviolet (near) -NUV-    400 - 300           3.10 - 4.13

Middle ultraviolet (middle) -MUV- 300 - 200      4.13 - 6.20

Far ultraviolet (far) -FUV-           200 - 122            6.20 - 10.16

Lyman-alpha -H line Lyman-α / Ly-α- 122 - 121    10,16 - 10,25

Vacuum ultraviolet -VUV-          200 - 10              6.20 - 124

UV ultraviolet -EU-                      121 - 10               10.25 - 124

The types of UV radiation (A B and C) are related to the damage they cause in humans: UV-C radiation is the most harmful to life.

<u><em>The answer is</em></u>: <u>The wavelength is approximately between 10 nm (10 x 10-9 m) and 400 nm (400 x 10-9 m).</u>

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Explanation:

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3 years ago
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2. A brick is sitting on a building 22 m high. It has a mass of 7.9 kg. What amount of potential
Citrus2011 [14]

Answer:

1703.24J

Explanation:

Given parameters:

Mass of brick  = 7.9kg

Height of building  = 22m

Unknown:

Potential energy of the brick  = ?

Solution:

The potential energy of a body is the energy at rest of the body. Mathematically;

 

         P.E = mgh

m is the mass of the brick

g is the acceleration due to gravity

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  Insert the given parameters and solve;

        P.E  = 7.9 x 9.8 x 22  = 1703.24J

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3 years ago
A 392 N wheel comes off a moving truck and rolls without slipping along a highway. At the bottom of a hill it is rotating at 24
alex41 [277]

Answer:

h=12.41m

Explanation:

N=392

r=0.6m

w=24 rad/s

I=0.8*m*r^{2}

So the weight of the wheel is the force N divide on the gravity and also can find momentum of inertia to determine the kinetic energy at motion

N=m*g\\m=\frac{N}{g}\\m=\frac{392N}{9.8\frac{m}{s^{2}}}

m=40kg

moment of inertia

M_{I}=0.8*40.0kg*(0.6m} )^{2}\\M_{I}=11.5 kg*m^{2}

Kinetic energy of the rotation motion

K_{r}=\frac{1}{2}*I*W^{2}\\K_{r}=\frac{1}{2}*11.52kg*m^{2}*(24\frac{rad}{s})^{2}\\K_{r}=3317.76J

Kinetic energy translational

K_{t}=\frac{1}{2}*m*v^{2}\\v=w*r\\v=24rad/s*0.6m=14.4 \frac{m}{s}\\K_{t}=\frac{1}{2}*40kg*(14.4\frac{m}{s})^{2}\\K_{t}=4147.2J

Total kinetic energy  

K=3317.79J+4147.2J\\K=7464.99J

Now the work done by the friction is acting at the motion so the kinetic energy and the work of motion give the potential work so there we can find height

K-W=E_{p}\\7464.99-2600J=m*g*h\\4864.99J=m*g*h\\h=\frac{4864.99J}{m*g}\\h=\frac{4864.99J}{392N}\\h=12.41m

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3 years ago
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4 years ago
A vessel that contains a gas has two pressure gauges attached to it. One contains liquid mercury, and the other an oil such as d
castortr0y [4]

Answer:

Pressure of the gas = 12669 (Pa) and height of the oil is 1,24 meters

Explanation:

First, we can use the following sketch for an easy understanding, in the attached image we can see the two pressure gauges the one with mercury to the right and the other one with oil to left. We have all the information needed in the mercury pressure gauge, so we can determine the pressure inside the vessel because the fluid is a gas it will have the same pressure distributed inside the vessel (P1).

Since P1 = Pgas, we can use the same formula, but this time we need to determine the height of the column of oil in the pressure gauge.

The result is that the height of the oil column is higher than the height of the one that uses mercury, this is due to the higher density of mercury compared to oil.

Note: the information given in the units of the fluids is not correct because the density is always expressed in units of (mass /volume)

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3 years ago
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