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SIZIF [17.4K]
3 years ago
15

The molar heat of fusion of gold is 12.550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to release

235.0 kJ of energy?
Chemistry
2 answers:
KIM [24]3 years ago
7 0

Answer:

the answer is d.

Explanation:

Excuse me while I go kill Thanos.

GuDViN [60]3 years ago
5 0
<span>The total heat released, Q, equals number of moles, n, times molar heat of fussion, Hf. this is: Q = n * Hf. You kno Q and Hf, so you can find n as n = Q/Hf = 235.0 kJ / 12.55 kJ/mol = 18.72 mol. Now you can pass that to mass using the atomic mass of Au, which is 197 g/mol => mass = 18.73 mol * 197 g/mol = 3688.9 grams.</span>
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How many moles of oxygen are necessary to react completely with four moles of propane (CH)?
steposvetlana [31]

Answer:

20 mole of oxygen

Explanation:

1 mole of proprane reacts with 5 moles of oxygen so 4 time 5 equals 20

7 0
3 years ago
The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when
Natasha_Volkova [10]

Answer: 0.52V

Explanation:

Ecell = Ecell(standard) - [(0.0592 logQ)/n]

Q = product of the quotient

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Ecell = 0.63 - [(0.0592*Log(1 / 2.0 * 10-4) / 2]

Ecell = 0.63 - 0.0194

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5 0
3 years ago
iron will react with oxygen to produce Fe2O3. how many grams of Fe2O3 will he produced if 0.18 mil of Fe reacts?
nasty-shy [4]

Answer:

14.4g

Explanation:

First, we need to write a balanced equation for the reaction between Fe and O2 to produce Fe2O3. This is illustrated below:

4Fe + 3O2 —> 2Fe2O3

From the balanced equation,

4moles of Fe produced 2moles of Fe2O3.

Therefore, 0.18mol of Fe will produce = (0.18x2) /4 = 0.09mol of Fe2O3.

Now we need to find the mass present in 0.09mol of Fe2O3. This can be achieved by doing the following:

Molar Mass of Fe2O3 = (56x2) + (16x3) = 112 + 48 = 160g/mol

Number of mole of Fe2O3 = 0.09mol

Number of mole = Mass /Molar Mass

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6 0
3 years ago
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Effectus [21]

Answer:

so that the can fiuger out what it is for the answer

Explanation:

3 0
3 years ago
348 g of water starting at 4.0°Celsius is heated until his temperature is 37°Celsius. Calculate the amount of heat energy needed
attashe74 [19]

Answer:

48.049 kJ or 48049 J

Explanation:

Hello again.

So we know the formula q = mc\Delta t. c is the heat capacity but this time, it is not given. However, water has a very well known heat capacity which is 4.184 J/(g°C). This is in fact the number we refer to a calorie which is the amount of energy you burn that can raise the temperature of 1g of water by 1°C. So, plugging in values, you get the above. But double check if I am wrong.

7 0
3 years ago
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