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3 years ago

Difference between static and kinetic friction in physics

1 answer:

4 0

The force of static friction keeps a stationary object at rest. Once the force of static friction is overcome, the force of kinetic friction is what slows down a moving object.

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A train having speed of 85 km/h takes 5 hours to travel from Kerala to Karnataka. Calculate the distance between Kerala and Karn

Morgarella [4.7K]

Answer:

the distance between Kerala and Karnataka is 425 km.

Explanation:

Given;

speed of the train, u = 85 km/h

time taken for the train to travel from Kerala to Karnataka, t = 5 hours

The distance between Kerala and Karnataka is calculated as;

Distance = speed x time

Distance = 85 km/h x 5 h

Distance = 425 km

Therefore, the distance between Kerala and Karnataka is 425 km.

6 0

3 years ago

1. What was the electromagnetic spectrum ?

Maurinko [17]

The answer is C. I hope this helps you.

4 0

3 years ago

What is the density of iron if 5.0 cm3 has a mass of 39.5g

weqwewe [10]

Answer : $\rho = 7.9\ g/cm^3$

Explanation :

It is given that

Mass of iron, m = 39.5 g

Volume of iron, $V = 5\ cm^3$

So, density is :

density, $\rho =\dfrac{mass}{volume}$

$\rho =\dfrac{39.5g}{5cm^3}$

$\rho = 7.9\ g/cm^3$

7 0

3 years ago

Two basketballs of equal mass are rolling toward each other at constant velocities. The first basketball (B1) has a velocity of

slamgirl [31]

$v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)$

<u>Explanation:</u>

Velocity of B₁ = 4.3m/s

Velocity of B₂ = -4.3m/s

For perfectly elastic collision:, momentum is conserved

$m_1v_1 + m_2v_2 = m_1v'_1 + m_2v'_2$

where,

m₁ = mass of Ball 1

m₂ = mass of Ball 2

v₁ = initial velocity of Ball 1

v₂ = initial velocity of ball 2

v'₁ = final velocity of ball 1

v'₂ = final velocity of ball 2

The final velocity of the balls after head on elastic collision would be

$v'_2 = \frac{2m_1}{m_1+m_2} v_1 - \frac{m_1-m_2}{m_1+m_2} v_2\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} v_1 + \frac{2m_2}{m_1+m_2} v_2$

Substituting the velocities in the equation

$v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)$

If the masses of the ball is known then substitute the value in the above equation to get the final velocity of the ball.

5 0

3 years ago

Please help

adelina 88 [10]

Answer:

I'm pretty sure that the answer is A

5 0

3 years ago