How many moles of Ca are in 3.75 x 10^25 atoms of Ca?

1 answer:

ioda2 years ago

7 0

<h3>Answer:</h3>

62.3 mol Ca

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

<u>Chemistry</u>

<u>Atomic Structure</u>

<u>Stoichiometry</u>

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.75 × 10²⁵ atoms Ca

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 3.75 \cdot 10^{25} \ atoms \ Ca(\frac{1 \ mol \ Ca}{6.022 \cdot 10^{23} \ atoms \ Ca})$
Multiply/Divide: $\displaystyle 62.2717 \ mol \ Ca$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

62.2717 mol Ca ≈ 62.3 mol Ca

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Gwar [14]

Answer:

$\huge\boxed{\sf Single \ displacement \ reaction}$

Explanation:

<h2><u>Displacement reaction:</u></h2>

A reaction in which an element displaces or replaces another element of a compound is called a displacement reaction.

<h3><u>Types:</u></h3>

There are 2 types:

<h3><u>1. Single displacement reaction:</u></h3>

If one element displaces 1 other element of a compound, it is called single displacement reaction.
<u>Example</u>: $CuSO_4 +Fe \longrightarrow \ FeSO_4 + Cu$
Here, 1 element (Fe) displaces 1 other element (Cu) of a compound.

<h3><u>2. Double displacement reaction:</u></h3>

If two elements in two compounds displace one another, it is called double displacement reaction.
<u>Example:</u> $CuSO_4+NaOH \longrightarrow Cu(OH)_2 + Na_2SO_4$
Here, Copper and sodium both displace each other.