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3 years ago

What volume does 14 mol of gas occupy at STP? Round to the nearest hundredth.

Chemistry

1 answer:

Anna007 [38]3 years ago

4 0

Answer:

The volume is 310 L

Explanation:

We use the ideal gas formula, with the constant R = 0.082 l atm / K mol. The STP conditions are 1 atm pressure and 273 K temperature. Solve for the formula, V (volume):

PV= nRT ---> V= (nRT)/P

V=( 14 mol x 0,082 l atm /K mol x 273 K)/ 1 atm

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Carbon-14 is a radioactive isotope that decays according to first-order kinetics in a process that has a half-life of 5730 years

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Explanation :

Half-life = 5730 years

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Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.21\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = ?

a = let initial amount of the reactant = X g

a - x = amount left after decay process = $71\% \times (x)=\frac{71}{100}\times (X)=0.71Xg$

Now put all the given values in above equation, we get

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{X}{0.71X}$

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