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Sedbober [7]
3 years ago
13

Count the number of each type of atom in the equation below, and then balance the equation. Write In the numbers of atoms and co

efficient. Add a 1 if there should be no coefficient.
CS2(I)+O2(g)-CO2(g)+SO2(g)

__C __ S __ - __C __S __O



__ CS2(I)+ __ O2(g)- __ CO2(g)+__ SO2(g)
​
Chemistry
2 answers:
Galina-37 [17]3 years ago
8 0

1,2,2,1,1,4 is the numbers for the first equation

Studentka2010 [4]3 years ago
4 0

Answer:

Balanced equation

CS2(l) + 3O2(g)------> CO2(g) + 2SO2(g)

Explanation:

For a chemical equation to be balanced, the number of atoms of each element on the left Hans side of the reaction equation must equal the number of atoms of that element on the right hand side of the reaction equation.

Atoms of oxygen are six on both sides of the reaction equation. Atoms of sulphur are two while there is only one atom of carbon on both sides of the reaction equation.

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A silver cube with an edge length of 2.36 cm and a gold cube with an edge length of 2.67 cm are both heated to 87.9 ∘C and place
Lunna [17]

Answer:

Hence, the final temperature is 28.3 °C .

Explanation:

Given, the edge length of the silver cube = 2.36 cm

The volume of the silver cube = (Edge/ length)^3 = (2.36)^3 cm³ = 13.144256 cm³

Given, the edge length of the gold cube = 2.67 cm

The volume of the gold cube = (Edge/ length)^3 = (2.67)^3 cm³ = 19.034163 cm³

Density is defined as:-

\rho=\frac{Mass}{Volume}

or,  

Mass={\rho}\times Volume

So, Density of silver = 10.5 g/cm³

<u>Thus, Mass of the silver cube = 10.5 g/cm³ * 13.144256 cm³ = 138.0147 g</u>

So, Density of gold = 19.3 g/cm³

<u>Thus, Mass of the gold cube = 19.3 g/cm³ * 13.144256 cm³ = 253.6841 g</u>

So, Density of water = 1 g/cm³

Given, Volume = 108.0 mL = 108.0 cm³

<u>Thus, Mass of the water = 1 g/cm³ * 108.0 cm³ = 108.0 g</u>

Heat gain by water = Heat lost by gold + Heat lost by silver

Thus,  

m_{water}\times C_{water}\times (T_f-T_i)=-m_{gold}\times C_{gold}\times (T_f-T_i)-m_{silver}\times C_{silver}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

m_{water}\times C_{water}\times (T_f-T_i)=m_{gold}\times C_{gold}\times (T_i-T_f)+m_{silver}\times C_{silver}\times (T_i-T_f)

<u>For water: </u>

Mass = 108.0 g

Initial temperature = 19.7 °C

Specific heat of water = 4.184 J/g°C

<u>For gold: </u>

Mass = 253.6841 g

Initial temperature = 87.9 °C

Specific heat of water = 0.1256 J/g°C

<u>For silver: </u>

Mass = 138.0147 g

Initial temperature = 87.9 °C

Specific heat of water = 0.2386 J/g°C

So,  

108.0\times 4.184\times (T_f-19.7)=253.6841\times 0.1256\times (87.9-T_f)+138.0147\times 0.2386\times (87.9-T_f)

108\times \:4.184\left(T_f-19.7\right)=31.86272296\left(-T_f+87.9\right)+32.93030742\left(-T_f+87.9\right)

451.872T_f-8901.8784=5695.30737 -64.79303038T_f

516.66503 T_f=14597.18577

T_f=\frac{14597.18577}{516.66503}

T_f = 28.25270\ ^0C

<u>Hence, the final temperature is 28.3 °C .</u>

7 0
3 years ago
Bài 19 với ạ, ai giúp em với ❤️❤️❤️❤️❤️
Bumek [7]

Answer:

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Explanation:

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3 0
3 years ago
Which formulas represent two polar molecules?
sergeinik [125]

Answer is: 3) H2O and HCl.

Polar molecules are water (H₂O) and hydrochloric acid (HCl).

Nonpolar molecules are carbon(IV) oxide (CO₂) and methane (CH₄).

Carbon(IV) oxide is nonpolar because CO₂ is linear molecule and the oxygen atoms are symmetrical (bond angles 180°).

Water is polar because of the bent shape of the molecule.

Hydrochloric acid has polar covalent chemical bond where hydrogen has oxidation umber +1  and chlorine oxidation number -1.

In molecule of methane (CH₄) all the atoms around the central element (carbon) are equivalent (four hydrogens) and it has a net dipole moment of 0 (vectors of dipole moments cancel each other, dipole moment is zero).

8 0
3 years ago
Read 2 more answers
Which metal will spontaneously react with Zn2+(aq), but will not spontaneously react with Mg2+(aq)?
DerKrebs [107]
Correct Answer: option <span>(1) Mn(s)

Reason: 
The </span><span>spontaneity of electrochemical cell, depends on the it's Eo value. Electrochemical cells with positve Eo are spontanous and vice-versa.
</span>
In present case, the  Eo of half-cell of interest are as follows:
Eo Zn2+/Zn = <span>-0.763v
</span>Eo Mg2+/Mg = 2.37v
Eo Mn2+/Mn = -1.18v

Therefore, Eo cell (with Zn as one of the half-cell) =  Eo Zn2+/Zn - Eo Mn2+/Mn
                                                                                =  -0.763 - (-1.18)
                                                                                = 0.417v

On other hand, Eo cell (with Mg as one of the half-cell) =  Eo Mg2+/Zn - Eo Mn2+/Mn
                                                                                =  -2.37 - (-1.18)
                                                                                = -1.19v

Thus, Mn(s) <span>metal will spontaneously react with Zn2+(aq), but will not spontaneously react with Mg2+(aq)</span>
8 0
3 years ago
What would happen if the lid of a jar filled with helium gad was removed?
yawa3891 [41]
The helium would expand into the air of the room. Depending on how big the room is, and the amount of helium in the jar, it could cause damage to health. The only way this would happen is if the room was small and the jar was big.

I hope this helps!
7 0
3 years ago
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